I would say the answer is 7, since 21 divided by 3 is 7 and there are 1/3 as many of them
Answer:
The area of the sector (shaded section) is 29.51 .
Step-by-step explanation:
Area of a sector = (θ ÷ 360)
where θ is the central angle of the sector, and r is the radius of the circle.
From the diagram give, diameter of the circle is 26 m. So that;
r =
= = 13 m
θ = 360 - (180 + 160)
= 360 - 340
=
Thus,
area of the given sector = x x
= x x x 169
= 29.5079
The area of the sector (shaded section) is 29.51 .
Answer:
M = -2/3
Step-by-step explanation:
2x + 3y = -12 (subtract 2x from both sides)
3y= -2x -12 (divide everything by 3)
Y = -2/3x - 4
M= -2/3
Answer:
<em>The graph is attached</em>
Covers the shaded space to the right from solid vertical line x = 2, which is parallel to y-axis
<u>Option C is likely the answer</u>
- A graph showing a range of negative three to two on the x and y axes. A solid line with arrows at both ends passes through the x axis at two and runs parallel to the y axis. The graph is shaded to the right of the line.
1. This function goes trough 3 points: ( 0,0),(8,0) and (4, -8) so we have to find f(0)=0, f(8)=0, f(4)= -8
f(0)= c=0✔️
f(8)=64 a +8b=0 divide by 4; 16a+2b=0 (1)
f(4)=16a+4b=-8 divide by 4; 4a+b= -2 (2)
From(2)
b=-4a-2
Substitute b in (1)
16 a+2( -4a-2)=0; 16a-8a-4=0; 8a=4
so a=1/2✔️
b=-2-2= -4✔️
The quadratic function is:
f(x)=(X^2)/2 -4x=0
2. This quadratic function goes trough points ( 2,12), (-4,0), (8,0)
The quadratic function is:
f(x)= (-x^2)/3. + 4x/3. +32/3
3. This quadratic function goes trough points ( 2, -6), (-1,0), (5,0)
The quadratic function is:
f(x)=(2x^2)/3. -8x/3. -10/3
4. This function goes trough points (0,2), (-2,0), (4,0)
The quadratic function is:
f(x)=(-x^2)/4. +x/2. +2