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Keith_Richards [23]
3 years ago
5

P2C.11 In biological cells that have a plentiful supply of oxygen, glucose is oxidized completely to CO2 and H2O by a process ca

lled aerobic oxidation. Muscle cells may be deprived of O2 during vigorous exercise and, in that case, one molecule of glucose is converted to two molecules of lactic acid (CH3CH(OH)COOH) by a process called anaerobic glycolysis. (a) When 0.3212 g of glucose was burned at 298 K in a bomb calorimeter of calorimeter constant 641 J K−1 the temperature rose by 7.793 K. Calculate (i) the standard molar enthalpy of combustion, (ii) the standard internal energy of combustion, and (iii) the standard enthalpy of formation of glucose. (b) What is the biological advantage (in kilojoules per mole of energy released as heat) of complete aerobic oxidation compared with anaerobic glycolysis to lactic acid?
Chemistry
1 answer:
blagie [28]3 years ago
8 0

Answer:

? explain better

Explanation:

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Ca (ClO) 2<br> Spell out the full name of the compound.
antoniya [11.8K]
Calcium hypochlorite
5 0
4 years ago
2. Food is another concern before the trip begins. Everyone has become accustomed to a 1500 calorie diet due the food
fomenos

About 46.1 pounds of apple would be needed per day of the trip.

I managed to extract the complete scenario from the attached image.

The trip is made up of 4 men and 3 women, making a total of 7 people.

Everyone has become accustomed to 1500 calories per day.

The total calories needed per day for 7 persons = 1500 x 7

                           = 10,500 calories

189 g of apple has only 95 calories, what g of apple will produce 10,500 calories?

                 = 10,500 x 189/95 = 20,889.67 g of apple

From conversion:

1 g = 0.00220462 pounds

20,889.67 g = 20,889.67 x 0.00220462

                         = 46.1 pounds of apple

More about dimensional analysis can be found here: brainly.com/question/22015862

8 0
3 years ago
Consider the chemical equation for the ionization of CH3NH2 in water. Estimate the percent ionization of CH3NH2 in a 0.050 M CH3
anyanavicka [17]

Answer:  The percent ionization of CH_3NH_2 in a 0.050 M CH_3NH_2(aq) solution is 8.9 %

Explanation:

CH_3NH_2+H_2O\rightarrow OH^-+CH_3NH_3^+

 cM                            0             0

c-c\alpha                       c\alpha            c\alpha

So dissociation constant will be:

K_b=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= concentration = 0.050 M and \alpha = degree of ionisation = ?

K_b=4.4\times 10^{-4}

Putting in the values we get:

4.4\times 10^{-4}=\frac{(0.050\times \alpha)^2}{(0.050-0.050\times \alpha)}

(\alpha)=0.089

percent ionisation =0.089\times 100=8.9\%

8 0
3 years ago
5. Identify one environmental problem caused by
Minchanka [31]

Answer:

High levels of nitrogen dioxide are also harmful to vegetation—damaging foliage, decreasing growth or reducing crop yields. Nitrogen dioxide can fade and discolour furnishings and fabrics, reduce visibility, and react with surfaces.

1-We could use low-nitrogen fuels

2- We could also modify combustion conditions to generate less NOx. Flue gas treatment techniques, such as selective cata- lytic reduction (SCR) processes, can remove NOx

6 0
3 years ago
Which are correct ???
pav-90 [236]

Answer:

last one

Explanation:

endothermic reactions release energy

7 0
3 years ago
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