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IgorC [24]
3 years ago
9

A 4m ladder rest against a vertical wall with its foot 2m from the wall.How far up the wall does the ladder reach?

Mathematics
1 answer:
adell [148]3 years ago
4 0

A) How high up the wall does it reach?

Use the Pythagorean theorem

Height^2 + Base^2 = Hyp^2

H^2+ 2^2 = 4^2         Subtract the 2^2 from both sides

H^2 = 4^2 -2^2          Multiply the square roots of both the numbers

H^2= 16 - 4

H^2 = 12

H= sqrt(12) m

Hope this helps

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cestrela7 [59]

The 3 inside angles of a triangle need to add up to 180 degrees.

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A = 180 - 104 - 36 - 40

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Gemiola [76]

4/6=2/3 (divide both numerator and denominator by 2 (gcd)).

Hope this helps.

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3 years ago
What is the value of x and z
saw5 [17]
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3 years ago
Solve for x...........................
yaroslaw [1]

Answer:

Option A is correct, i.e. x = -3, x = 7.

Step-by-step explanation:

Given the equation is x² -4x -21 = 0.

We can compare it with general quadratic equation i.e. ax² +bx +c =0.

then a = 1, b = -4, c = -21.

We can use Quadratic formula as follows:-

x = ( -b ± √(b²-4ac) )/2a

x = ( +4 ± √(16-4*1*-21) )/2*1

x = ( +4 ± √(16+84) )/2

x = ( +4 ± √(100) )/2

x = ( +4 ± 10 )/2

x = (4+10)/2 or x = (4-10)/2

x = 14/2 or x = -6/2

x = 7 or x = -3

Hence, option A is correct, i.e. x = -3, x = 7.

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3 years ago
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