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zloy xaker [14]
3 years ago
10

A line passes through the point (0, 1) and has a positive slope. Which of these points could that line NOT pass through? Check a

ll that apply. (12, 3) (-2,-5) +(-3, 1) O (1, 15) (5,-2)​
Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

  • (-3, 1)
  • (5,-2)​

Step-by-step explanation:

<h3>Given a line with</h3>
  • The point (0, 1) on it
  • A positive slope
<h3>To find </h3>
  • The point from the list that is not on the same line
<h3>Solution</h3>
  • <em>Slope formula is m = (y2 - y1)/(x2 - x1)</em>

<u>Using one given point, we get the slope:</u>

  • m = (y - 1)/(x - 0)
  • m = (y - 1)/x and m > 0
<h3>Let's verify the answer choices</h3>

<u>Point (12, 3)</u>

  • m = (3- 1)/12 = 2/12 > 0, yes, on the line

<u>Point (-2,-5) </u>

  • m = (-5 - 1)/( -2) = 3 > 0, yes, on the line

<u>Point (-3, 1) </u>

  • m = (1 - 1)/(-3) = 0, no, not on the line

<u>Point (1, 15) </u>

  • m = (15 - 1)/1 = 14 > 0, yes, on the line

<u>Point (5,-2)​</u>

  • m = (-2 - 1)/5 = -3/5 < 0, no, not on the line
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Answer:

The answers to the question is

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Step-by-step explanation:

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Here will be required to develop the periodic motion equation thus

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therefore the  we have T = 2π/k = 15

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also we note that the center of the wheel is 6 m above ground

We write our equation in the form

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When Jamie is 9 meters above the ground and rising we have

9 = 5*sin(\frac{2*\pi*t}{15} )+6 or 3/5 = sin(\frac{2*\pi*t}{15} ) = 0.6

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(b) Jamie is rising most rapidly when   the velocity curve is at the highest point, that is where the slope is zero

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\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15}) =0, π, 2π

Therefore -sin(\frac{2\pi t}{15} ) = 0 whereby t = 0 or

\frac{2\pi t}{15} = π and t =  7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = - 2/3π m/s which is decreasing

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The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

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The rate charged per hour by each mechanic was:  x = 75 $ / hr and y = 115 $ / hr.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given;

The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours.

Together they charged a total of $3225.

For this case we have the following variables:

x be the amount of $ / hr that the mechanic obtains 1.

y be the amount of $ / hr obtained by mechanic 2.

An equation to express this would be:

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Solving the system of equations we have:

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Hence, the rate charged per hour by each mechanic was:

x = 75 $ / hr

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