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3 years ago

What are 7 good facts on Computer Viruses?

1 answer:

4 0

Viruses,A tiny program that hacks a computer 
Steals information and personal data.It can disable your laptop.Viruses can be found in malicious sites.Criminals share these viruses to steal data from others.With a firewall,Hackers will be detected.

The general consensus is that there are no good viruses.

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What is the basic unit for storing data in exel

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A cell is the basic unit for storing data in exel

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3 years ago

What is meant by byte in computer terminology

dsp73

Answer:

Byte, the basic unit of information in computer storage and processing. A byte consists of 8 adjacent binary digits (bits), each of which consists of a 0 or 1. The string of bits making up a byte is processed as a unit by a computer; bytes are the smallest operable units of storage in computer technology.

Explanation:

Can I be brainliest? TYSMMMMMM

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3 years ago

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Write a program that creates a two-dimensional array named height and stores the following data:

antiseptic1488 [7]

Answer:

Explanation:

The following code is written in Java and it simply creates the 2-Dimensional int array with the data provided and then uses the Arrays class to easily print the entire array's data in each layer.

import java.util.Arrays;

class Brainly {

public static void main(String[] args) {

int[][] arr = {{16, 17, 14}, {17, 18, 17}, {15, 17, 14}};

System.out.print(Arrays./*Remove this because brainly detects as swearword*/deepToString(arr));

}

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3 years ago

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An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .

Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

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4 years ago

Someone help meeeeeeeee plz.......................

xenn [34]

Answer:

B-2

C-3

1/9

Explanation:

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3 years ago

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