Perimeter of quadrilateral ANCM = AN+NC+CM+MA
CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.
Perimeter (P) = 4x in
Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in
Therefore, P=4*20.5 = 82 in
Put a photo or something so we can answer
Answer: Both 14, and 20
Step-by-step explanation:
Answer:
equation for perpendicular bisector passing through CB is;
y=⁴/³– 5/30
Answer:
( y^2 +1) ( x^2+1)
Step-by-step explanation:
Step 1 ) Factor out x^2 from the expression
x^2 (y^2+1)+y^2+1
Step 2) Factor out y^2 from the expression
(y^2+1) (x^2+1)
Solution is ( y^2 +1) ( x^2+1)