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AleksandrR [38]
2 years ago
11

A car drives at 45 km/h for 3 hours. How far does the car travel?

Mathematics
2 answers:
stellarik [79]2 years ago
8 0

Answer:

Hey!

The car travelled 135 kilometers!

Step-by-step explanation:

Here you have to do the speed (45km/h) multiplied by the time (3 hours)

45 x 3 = 135

So the car has travelled 135 kilometers!

HOPE THIS HELPS!!

cluponka [151]2 years ago
8 0
Answer: 135
Explanation: it is multiplying 45km by 3 and it equals 135km
If I helped please mark me brainliest
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A ladder 10 m long,leans against a vertical wall at an angle of 70° to the ground.if the ladder slips down the wall 4m,find,corr
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Answer:

(a) the new angle the ladder makes with the ground is 32.7^o

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m

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Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o

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cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4  \,\,m

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cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

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Step-by-step explanation:

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