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aalyn [17]
4 years ago
7

By rounding to one significant figure 615 x 38​

Mathematics
1 answer:
Lunna [17]4 years ago
6 0

Answer:

20000

Step-by-step explanation:

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Answer with explanation<br> I will and rate on the feedback.<br> Will mark brainliest too
yarga [219]

Answer: 6.6

Step-by-step explanation:

We have two triangles. Find the hypothenuse of the first triangle to make it easier to solve the second triangle.

First triangle:

a = 6

b = 8

c = ?

Use pythagorean's theorem

c^2=a^2+b^2\\c=\sqrt{a^2+b^2}

c=\sqrt{(6)^2+(8)^2}\\ c=\sqrt{36+64}\\ c=\sqrt{100}\\ c=10

This hypothenuse is valid for both triangles. Having said this, we already have 2 sides of the second triangle; c and a. We need to find b.

c^2=a^2+b^2\\b^2=c^2-a^2\\b=\sqrt{c^2-a^2}

b=\sqrt{(12)^2-(10)^2}\\ b=\sqrt{144-100}\\ b=\sqrt{44}\\ b=6.6

6 0
3 years ago
Look at this graph:
zavuch27 [327]
The slope will be 1/3
5 0
3 years ago
Read 2 more answers
Write and solve an equation twice a number is 26​
Svet_ta [14]

Answer:

2x = 26, x = 13

Step-by-step explanation:

Write and solve an equation twice a number is 26

x = unknown number

Equation: 2x = 26

Solve:

2x = 26

/2    /2 <== divide both sides by 2

x = 13

Check your answer:

2x = 26

2(13) = 26

26 = 26

This stament is correct

Hope this helps!

4 0
2 years ago
6–[(−3)+(−7)]–[(−1)–(−5)–(−8)] help me
stellarik [79]

Answer:

4

Copy it, paste it on a new tab, bada Bing Bada Boom, google, the thing that gets me past school.

5 0
3 years ago
If x = 4 tan(θ), find sec(θ) in terms of x
prisoha [69]

Answer:

\sec \theta =  \pm \frac{ \sqrt{ {x}^{2}  + 16} }{4}

Step-by-step explanation:

\because \: x = 4 \tan \theta \\   \therefore\frac{x}{4}  =  \tan \theta....(1) \\ \\  \because \:  { \sec}^{2}  \theta = 1 +  { \tan}^{2}   \theta \\ \therefore \:   \sec \theta =   \pm\sqrt{1 +  { \tan}^{2}   \theta }  \\  \therefore \:   \sec \theta =  \pm\sqrt{1 +  {  \bigg(   \frac{x}{4} \bigg)}^{2}    }  \\ \therefore \:   \sec \theta =  \pm\sqrt{1 +  {   \frac{x^{2}}{16} }    }  \\  \therefore \:   \sec \theta =  \pm\sqrt{{   \frac{16 + x^{2}}{16} }    }  \\ \therefore \:   \sec \theta =  \pm \frac{ \sqrt{ {x}^{2}  + 16} }{4}

3 0
3 years ago
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