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viktelen [127]
3 years ago
15

Equivalent expression for 6(x plus 2y)- 2(y-2x)

Mathematics
1 answer:
irinina [24]3 years ago
4 0

Answer:

X+2y+x+2

=2x+2y+2

=2(x+y+1

Step-by-step explanation:

The expression is similar to 2(x+y+1)

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Use Newton's method with initial approximation x1 = 1 to find x2, the second approximation to the root of the equation x4 − x −
drek231 [11]

Answer:

x_{2} = 0.0000

Step-by-step explanation:

The formula for the Newton's method is:

x_{i+1} = x_{i} + \frac{f(x_{i})}{f'(x_{i})}

Where f' (x_{i}) is the first derivative of the function evaluated in x_{i}.

x_{i+1} = x_{i} + \frac{x_{i}^{4}-x_{i}-3}{4\cdot x_{i}^{3}-1}

Lastly, the value of x_{2} is determined by replacing x_{1} with its numerical value:

x_{2} = x_{1} + \frac{x_{1}^{4}-x_{1}-3}{4\cdot x_{1}^{3}-1}

x_{2} = 1.0000 + \frac{1.0000^{4}-1.0000-3}{4\cdot (1.0000)^{3}-1}

x_{2} = 0.0000

8 0
3 years ago
PLEASE PLEASE PLEASE HELP ME YALL‼️‼️‼️‼️‼️
Inessa [10]

Answer:

Hi .. im happy to help

answer is 0.033

Step-by-step explanation:

P = C(4,4)÷C(10,4)

P = 1 ÷ 30

p =  \frac{1 }{30}

p = 0.033

3 0
3 years ago
Question number 8. Prove that 3 + √5 is an irrational number.​
Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

\\  \sf \: 3 +  \sqrt{5}  =  \frac{a}{b}   \\  \\   \qquad \: \tiny \sf{(where \:  \: a \:  \: and \:  \: b \:  \: are \:  \: integers \:  \: and \:  \: b \:  \neq \: 0)} \\

\\  \sf \:  \sqrt{5}  =  \frac{a}{b}  - 3 =  \frac{a - 3b}{b}  \\

Since, a, b and 3 are integers. So,

\\ \sf \:  \frac{p - 3b}{b}  \\  \\  \qquad \tiny \sf{ \: (is \:  \: a \:  \: rational \:  \: number \:) } \\

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

\\

Hence, 3 + √5 is an irrational number.

7 0
4 years ago
The weight of 1000 identical samples of a substance is 1 pound what is the weight of 10 samples
fenix001 [56]

is .001 pound

this is the correct answer

5 0
3 years ago
What is the answer for (a^2+12c)÷7b-1
vodomira [7]

Answer:

Step-by-step explanation:

Integer roots:

a = 6 n + 1, b = 7, c = -3 n^2 - n, n element Z

a = 6 n + 5, b = 7, c = -3 n^2 - 5 n - 2, n element Z

Derivative:

d/da(1/7 (a^2 + 12 c) b - 1) = (2 a b)/7

Indefinite integral:

integral(-1 + 1/7 b (a^2 + 12 c)) da = (a^3 b)/21 + (12 a b c)/7 - a + constant

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5 0
3 years ago
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