Answer:
1. 24.36
2. Do the same thing (follow the steps in the picture)
Step-by-step explanation:
Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
Answer:
complimemtary
Step-by-step explanation:
We need two numbers that when multiplied will give you -40 and when added will give you -3:
(x+5) (x-8) this is your answer. And you want to know the process Here it goes. And attached is a chart I made you so you can visually see what this process is telling you:
1) identify a,b, and c in the trinomial ax^2 + bx+c (in your case it's 1x^2-3x-40= x^2-3x-40)
2) write down all factor pairs of c (numbers that multiplied produce -40)
3) identify which factor pair from the previous step sums up to b
4) Substitute factor pairs into two binomials
