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Andre45 [30]
3 years ago
5

Please help!!!!!! If ten = x what is 7x + 93x divided by 3.2x

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
6 0

Answer:

The answer is 2876.25

Step-by-step explanation:

The question said x is ten

so 7x means 7*10

93x means 93×10

divided by 3.2x which means 3.2x which is 3.2×10

when u write it in an equation format it will look like this 70+930÷32

Ur answer should look like this 2976.25

Sedaia [141]3 years ago
3 0

Answer:

The answer is 31.25 or 125/4 or 31 1/4 .

Step-by-step explanation:

You have to substitue x = 10 into the expression :

\frac{7x + 93x}{3.2x}

=  \frac{100x}{3.2x}

Let x = 10,

\frac{100(10)}{3.2(10)}

=  \frac{1000}{32}

=  \frac{125}{4}

= 31.25

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If AC = x + 5 and AB = 3x - 1... what is the length of BC?
Hatshy [7]
If B is the midpoint of AC, then |AB| = |AC|.
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Therefore we have the equation:
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Read more on Brainly.com - brainly.com/question/11324096#readmore
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4 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
2 years ago
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