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3 years ago

(01.05 MC)The total charge on 8 particles is −56 units. All the particles have the same charge.

Mathematics

1 answer:

AnnZ [28]3 years ago

6 0

Answer:

-7 units

Step-by-step explanation:

The charge on each of the 8 particles is 1/8 of the total charge, so is ...

-56 units / 8 = -7 units . . . charge on each particle

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Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

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$\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}$

$\Rightarrow \frac{radius }{height}=\frac {3}{26}$

$\Rightarrow radius=\frac {3}{26}\times height$ ......(1)

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Now putting $r=\frac{3}{26} h$

$V=\frac13 \pi (\frac3{26}h)^2 h$

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Differentiating with respect to t

$\frac{dV}{dt}=\frac{3}{676}\pi .3h^2 \frac{dh}{dt}$

$\Rightarrow \frac{dV}{dt}=\frac{9}{676}\pi h^2 \frac{dh}{dt}$

Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e $\frac{dh}{dt}=17$ cm/min

Putting $\frac{dh}{dt}=17$

$\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17$

$\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17$

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The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

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