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3 years ago

Simplify (6x^2 - 3 - 5x^3) - (4x^3 +2x^2 - 8)

Mathematics

1 answer:

yanalaym [24]3 years ago

6 0

Answer:

-9x^3+4x^2+5

Step-by-step explanation:

(6x^2 - 3 - 5x^3) - (4x^3 +2x^2 - 8)

distribute the minus sign

(6x^2 - 3 - 5x^3) - 4x^3 -2x^2 + 8

Combine like terms

-5x^3 -4x^3 +6x^2 - 2x^2 -3 +8

-9x^3+4x^2+5

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Bas_tet [7]

Answer:

a) We reject H₀ We find difference between the mean of the two groups

b) we accept H₀ : There is no statistical difference ( in the scale of pain) when the difference in samples means is 1

Step-by-step explanation:

Group 1: Only with educational material

Sample size n₁ = 42

Sample mean x₁ = 3,2

Sample standard deviation s₁ = 2,3

Group 2: With exercises with the treatment of individuals

Sample size n₂ = 42

Sample mean x₂ = 5,2

Sample standard deviation s₂ = 2,3

Test Hypothesis

Null Hypothesis H₀ x₂ - x₁ = 0 or x₁ = x₂

Alternative Hypothesis Hₐ x₂ - x ₁ > 0 or x₂ > x₁

Significance level α = 0,01

Sample sizes are n₁ = n₂ > 30

We use z-test

for α = 0,01 z(c) ≈ 2,32

To calculate z(s)

z(s) = ( x₂ - x₁ ) / √ (2,3)²/42 + (2,3)²/42

z(s) = ( 5,2 - 3,2 )/ √0,2519

z(s) = 2 / 0,5

z(s) = 4

Comparing z(s) and z(c)

z(s) > z(c)

z(s) is in the rejection region. We reject H₀ the true average pain level for the control condition exceeds that for the treatment condition.

b) Does the true average pain level for the control condition exceed that for the treatment condition by more than 1.

In this case

z( s) = x₂ - x₁ / 0,5

z(s) = 1 /0,5

z(s) = 2

Comparing z(s) and z(c) now

z(s) < z(c) 2 < 2,32

And z(s) is in the acceptance region ( for the same significance level) and we should accept H₀ equivalent to say that the two groups statistical have the same mean

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Step-by-step explanation:

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2 years ago

Evaluate the expression 3xy - 2x^2 for x=4 and for y = 3<br><br> helpp

hram777 [196]

3*4*3-2*4^2 = 36-32 = 4

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3 years ago

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Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of

Lunna [17]

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

$SI = \frac{P \times T \times R}{100}$

First account: $SI=\frac{x \times 1 \times 12}{100}$

Second account : $SI =\frac{(6000-x) \times 1 \times 7}{100}$

We are given that At the end of the first year he had earned $590 in interest.

So, $\frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400$

So,the amount in the account at 12% interest is $3400

The amount in the second account at 7% interest =6000-x=6000-3400=2600

Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

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