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4 years ago

Jacobi bought 7 1/2 pounds of meatballs He decide to cook 1 1/4 pounds and freeze the rest How many pounds did he freeze

Mathematics

2 answers:

Allushta [10]4 years ago

6 0

Answer:

he froze 6 1/4 pounds

Step-by-step explanation:

7 1/2 - 1 1/4 = 6.25

6.25 in fraction form is 6 1/4.

anygoal [31]4 years ago

3 0

If you take 1 off seven and 1/4 of 1/2 you get (6 1/4)

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Find 9x503. Show your work and explain why the strategy you chose works best with the factors?

kompoz [17]

503
x 9
———
4,527

This works good with the factors because you work step by step, making an equation like this one

5 0

3 years ago

a farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. no fencing is needed along the bar

xenn [34]

The constraint for the maximum enclosed area is the amount the farmer is

willing to spend on fencing.

The width of the plot that will give the most area, y = 83. $\underline{\overline 3}$ feet

The length of the plot that will give the most area, y = 125 feet

Reasons:

The given parameters are;

The cost of fencing per foot = $20

The maximum amount the farmer is willing to spend = $5000

Number of sides of fencing = 3 sides

Cost of the west side of the = Split with neighbor

Solution:

Let, y, represent the length of the fence, and let x represent the width of

the fence, we have;

Length of fence required = y + 2·x

Cost of the fence = 20·y + 20·x + (20÷2)·x = 20·y + 30·x

Therefore;

Maximum amount to be spent on the fence, 5000 = 20·y + 30·x

$\therefore y = \dfrac{5000 - 30 \cdot x}{20} = 250 - \dfrac{3}{2} \cdot x$

$y = \mathbf{250 - \dfrac{3}{2} \cdot x}$

Area of a rectangle = Length × Width

The enclosed rectangular area of the fencing, A = y × x

$\therefore A = \left(250 - \dfrac{3}{2} \cdot x\right) \cdot x = 250 \cdot x - \dfrac{3}{2} \cdot x^2$

$\therefore A = -\mathbf{ \dfrac{3}{2} \cdot x^2 + 250 \cdot x}$

The leading coefficient of the quadratic function of the area is negative,

therefore, the function only has a maximum point.

At the point of the most area, the slope, $\dfrac{dA}{dx} = 0$

Finding the value of x at the maximum point, we get;

$\dfrac{dA}{dx} = \mathbf{ \dfrac{d}{dx} \left( 250 \cdot x - \dfrac{3}{2} \cdot x^2\right)} = 250- 3 \cdot x = 0$

Therefore;

$\mathrm{ The \ width \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ x = \dfrac{250}{3} \ feet = \underline{83.\overline 3 \ feet}$

$\mathrm{ The \ length \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ y = 250 - \dfrac{3}{2} \times \dfrac{250}{3} = 125$

The length of the plot that will give the most area, y = 125 feet

Learn more here:

brainly.com/question/16337916

brainly.com/question/16545343

6 0

3 years ago

Consider the system of inequalities and its graph. y ≤ –0.75x y ≤ 3x – 2 In which section of the graph does the actual solution

lora16 [44]

We need to assign a value for x to check the possible values of y. 1st inequality: y < -0.75x X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT 2nd inequality: y < 3x -2 X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT X = 1 ; y < 3(1) – 2 ; y < 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT The actual solution to the system lies on the 4TH QUADRANT.

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3 years ago

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2/5 of a number is 40. What is 1/10 of the number Please help me

Ahat [919]

Answer:

Step-by-step explanation:

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3 years ago

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Describe a situation that can be represented by the expression 4(-2)

Alisiya [41]

I think the statement is missing in the question.
Let's assume it to be :
Describe a situation that can be represented by the expression 4(X-2)
According to that we can say:

A functions is define by Four times the difference of a number X and two.
Hope it helps.

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3 years ago

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