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Sveta_85 [38]
3 years ago
10

WILL GIVE BRAINLIEST

Mathematics
1 answer:
tester [92]3 years ago
8 0
The answer would be
D) 40
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In a pair of complementary angles, the larger angle is six more than three times the smaller angle. the measures of the angles a
harina [27]
2 angles are Complementary, if the sum of their measures = 90°.

Let the 2 angles be A and B, and let their measures be m(A)=a, m(B)=b.

Let A be the larger angle.



"the larger angle is six more than three times the smaller angle."

can be 'translated' into algebra as:   a = 6 + 3b

Also, since A and B are complementary, we have a+b=90°.


substitute a=6+3b in the second equation:

a+b=90°

(6°+3b+b)=90°


4b=90°-6°

b=84°/4=21°



Then, a = 90°-21°=69°


Answer: a= 69°, b=21°
7 0
3 years ago
Which relation is a function ?
NISA [10]

The correct option has been marked in the Figure below. A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function and the set B contains the range (also called the set of outputs).


For our correct option we have:

<u>Set A, Domain:</u>

Inputs: -2, 1, 0, 1, 2, 3


<u>Set B, Range:</u>

Outputs: -1, 0, 1, 2, 3


This is a function because this is a relation that assigns to each element x in the set A exactly one element y in the set B. So, the assignation is as follow:

  • -2 (in x) matches to 0 (in y)
  • -1 (in x) matches to 3 (in y)
  • 0 (in x) matches to 2 (in y)
  • 1 (in x) matches to -1 (in y)
  • 2 (in x) matches to 0 (in y)
  • 3 (in x) matches to 2 (in y)

4 0
3 years ago
Read 2 more answers
Can someone please help me with this question thank you
Burka [1]

Answer:

B & D

Step-by-step explanation:

5 0
4 years ago
Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).
Zina [86]

we are given

\sqrt{30} *\sqrt{610}

we can radical formula

\sqrt{a} *\sqrt{b}=\sqrt{a*b}

we get

\sqrt{30} *\sqrt{610}=\sqrt{30*610}

\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}

we can  also write as

\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}

\sqrt{30} *\sqrt{610}=10\sqrt{183}............Answer


7 0
4 years ago
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Simplify <br> −5x^4(−3x^2+4x−2)
malfutka [58]
112 me dió a eso mira haber si es si no trate.
6 0
3 years ago
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