Question

This parabola has x-intercepts

Answer 1

Answer:

see the explanation

Step-by-step explanation:

we have the quadratic equation

$y=-16x^{2} +32x-10$

This is a vertical parabola open downward

The vertex is a maximum

Find the x-intercepts of the quadratic equation

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

$-16x^{2} +32x-10=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16x^{2} +32x-10=0$        

so

$a=-16\\b=32\\c=-10$

substitute in the formula

$x=\frac{-32(+/-)\sqrt{32^{2}-4(-16)(-10)}} {2(-16)}$

$x=\frac{-32(+/-)\sqrt{384}} {-32}$

$x=\frac{-32(+/-)8\sqrt{6}}{-32}$

$x=\frac{-32(+)8\sqrt{6}}{-32}=\frac{32(-)8\sqrt{6}}{32}=0.39\ sec$

$x=\frac{-32(-)8\sqrt{6}}{-32}=\frac{32(+)8\sqrt{6}}{32}=1.61\ sec$

therefore

This parabola has two x-intercepts representing the times when the dolphin's height above water is zero feet

Answer 2

Answer:

This parabola has 2 x-intercepts

Representing the times when the dolphin's height above water is 0 feet

There are two real solutions to this equation,  representing the number of seconds elapsed between the dolphin exiting and reentering the water.

Step-by-step explanation:

That's all the answers for this whole slide :)