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allochka39001 [22]

3 years ago

12

When asked to find a number one-tenth as large as another number, what operation would you use? What about when asked to find a

number 10 times as large?

1 answer:

marishachu [46]3 years ago

8 0

That's question is unknown

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A car salesman receives a base weekly salary of $150 plus a commission of $325 per car sold. What is the equation that models th

Temka [501]

Given :

Weekly salary , S = $150.

Commission per car , C = $325.

To Find :

The the equation that models the weekly salary of a car salesman.

Solution :

We know it is a quadratic equation :

Let , the equation is , y = mx + c

Here, x is number of car sold in a week.

For x = 0 ( He will not get commission)

So , Salary is $150 = c .

For x = 1

Salary is $( 150 + 325 ) = $475 = m(1) + c

Therefore , m = $325 and c = $150.

Required linear equation is y = 325x + 150.

Hence, this is the required solution.

5 0

3 years ago

Perform the indicated operation.<br><br> 14 - (-10)

Rashid [163]

The answer for that is 24.

3 0

3 years ago

Read 2 more answers

Could someone help please

leonid [27]

Answer: B

<u>Step-by-step explanation:</u>

There are 26 letters in the alphabet. D is the 4th letter, so there are 26 - 4 = 22 letters after D.

$\frac{22}{26}$ ÷ $\frac{2}{2}$ = $\frac{11}{13}$

3 0

3 years ago

Find the inverse: f(x)=x+5/3x-1<br><br> f^-1x=

babunello [35]

We have $f(x)=\dfrac{x+5}{3x-1}$ .

To find inverse function $f^{-1}(x)$ we substitute x with $f^{-1}(x)$ and vice-versa to get

$x=\dfrac{f^{-1}(x)+5}{3f^{-1}(x)-1}$

Now solve for $f^{-1}(x)$ . Note that I will use $j$ instead.

$x=\dfrac{j+5}{3j-1} \\x(3j-1)=j+5 \\3jx-x=j+5 \\3jx-x-j-5=0 \\3jx-j=x+5 \\j(3x-1)=x+5 \\j=\dfrac{x+5}{3x-1}$

So we find that $f(x)=f^{-1}$ .

Hope this helps.

7 0

3 years ago

Read 2 more answers

If you could do this you’re the best and you’ll also get a lot of points thanks

Andre45 [30]

Answer:

take the answer on picture which I attached with your question

3 0

3 years ago