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3 years ago

Choose the number that has a 5 with a value 10 times less than the value of the 5 in the number in 54,271

Mathematics

1 answer:

Zigmanuir [339]3 years ago

6 0

The answer is 500,000 because you have add a zero sense it's times 10

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Write a word problem that involves combining three equal groups

MakcuM [25]

The larger number is 7 more than the smaller. Three times the larger number is 5 more than 4 times the smaller number. Find the numbers.

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4 years ago

The cost of a catering prom is 250 plus $15 for each person attending. what is the cost of 150 people?

Anastasy [175]

Answer:

$2500

Step-by-step explanation:

First, multiply the $15 for the 150 people attending, to get 2250. Next, add the last $250 to get a total cost of $2500

Hopefully this helps- let me know if you have any questions!

4 0

3 years ago

Read 2 more answers

280 is what percent of 400?

skad [1K]

It would be 70% of 400

490(.7) = 280

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3 years ago

Read 2 more answers

8x+5y=40 How to find a slope

ololo11 [35]

Answer:

the slope is -8/5

Step-by-step explanation:

we need to get the equation in the form

y= mx+b where m is the slope and b is the y intercept

8x + 5y =40

subtract 8x from each side

8x-8x + 5y = -8x +40

5y = -8x+40

divide each side by 5

5y/5 = -8x /5 + 40/5

y = -8/5 x +8

the slope is -8/5 and the y intercept is 8

8 0

3 years ago

You need to compute the a 90% confidence interval for the population mean. How large a sample should you draw to ensure that the

RSB [31]

Answer:

The sample size required is 102.

Step-by-step explanation:

The (1 - α)% confidence interval for population mean μ is:

$CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

Given:

σ = 9.2

(1 - α)% = 90%

MOE = 1.5

The critical value of z for 90% confidence level is:

$z_{0.10/2}=1.645$

*Use a z-table.

Compute the value of n as follows:

$MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}$

$=[\frac{1.645\times 9.2}{1.5}]^{2}\\=101.795\\\approx102$

Thus, the sample size required is 102.

5 0

3 years ago