Need mor information in order to amseer this
Exactly right down to the last step, but some errors in combining terms.
(6m^5 + 3 – m^3 – 4m) – (–m^5 + 2m^3 – 4m + 6)
= (6m^5 + 3 – m^3 – 4m) + (m^5 – 2m^3 + 4m – 6)
= 6m^5 + 3 + (–m^3) + (–4m) + m^5 + (–2m^3) + 4m + (–6)
= [6m^5 + m^5] + [3 + (–6)] + [(–m^3) + (–2m^3)] + [(–4m) + 4m]
= (6+1)m^5 +(-1-2)m^3 +(-4+4)m +(3-6)
= 7m^5 – 3m^3 – 3
Answer:
The value of a which equation have 2 , -
Step-by-step explanation:
Given expression as :
2 a - 4 x = 4 - a² × x
The equation lies in the interval ( - 8 , - 2 )
∵ equation lies in the interval , so it must satisfy the equation
So , 2 a - 4 × ( - 8 ) = 4 - a² × ( - 8 )
Or, 2 a + 32 = 4 + 8 a²
Or, a + 16 = 2 + 4 a²
So, equation can be written as :
4 a² - a - 14 = 0
Or, 4 a² - 8 a + 7 a - 14 = 0
Or, 4 a ( a - 2 ) + 7 ( a - 2 ) = 0
Or, ( a - 2 ) ( 4 a + 7 ) = 0
∴ a = 2 And -
Hence The value of a which equation have 2 , -
Answer
Answer:
12 i think
Step-by-step explanation:
hope it helps
Answer:
120º
Step-by-step explanation:
First we need to know the fraction of the area of ORT to the area of the circle.
Fraction = 18π/54π = 1/3
We know that a circle is 360º, and sector ORT is xº. The fraction of the sector of ORT to the circle must also be equal to 1/3.
x/360 = 1/3
3x = 360
x = 120º