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3 years ago

Plz plz plz plz plz plz plz plz plz

Mathematics

1 answer:

Andreas93 [3]3 years ago

4 0

13500 m in 250 s
s is the second rate

deomenator is bottom number in a/b, denomenator is b

13500m/250s
use clculator or something to divide or use head
54m/s

answer is A

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Donna is on the swim team. Each week she swims a total of 8000 meters. How many kilometers does she swim each week? Be sure to i

aivan3 [116]

Answer:

Donna swims 8 km each week.

Step-by-step explanation:

To be able to find the answer, you have to consider that 1 km is equal to 1000 meters and with this, you can use rule of three to find the kilometers in 8000 meters:

1 km → 1000 meters

x ← 8000 meters

x=(1*8000)/1000=8 km

According to this, the answer is that Donna swims 8 km each week.

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3 years ago

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Dennis_Churaev [7]

Answer: (B is the answer.

Step-by-step explanation: The graph I attached corresponds with B.

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3 years ago

Which of the following represents "the square of the sum of a number and 4 is 36"? x2 + 42 = 36 x2 + 4 = 36 (x + 4)2 = 36

MrRa [10]

<span>"the square of the sum of a number and 4 is 36"
=
</span><span>(x + 4)^2 = 36

</span>

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3 years ago

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What value of x makes the equation 66x = 6 true

KatRina [158]

Answer:

66 x 1/11 = 6

66 x 0.09 = 6

So x = either 1/11 or 0.09

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3 years ago

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Question in pictures

yan [13]

The derivatives of the functions are listed below:

(a) $f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}$

(b) $f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }$

(c) f'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)²

(d) f'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)]

(e) f'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶

(f) $f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}]$

(g) $f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) - \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2} \cdot x^{-\frac{1}{2} }\right)$

(h) f'(x) = cot x + cos (㏑ x) · (1 / x)

<h3>How to find the first derivative of a group of functions</h3>

In this question we must obtain the <em>first</em> derivatives of each expression by applying <em>differentiation</em> rules:

(a) $f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}$

$f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}$ Given
$f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4\cdot x - \frac{x}{5} + 5 \cdot x^{-1} - \sqrt[11]{2022}$ Definition of power
$f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}$ Derivative of constant and power functions / Derivative of an addition of functions / Result

(b) $f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}$

$f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}$ Given
$f(x) = (x + 3)^{\frac{1}{3} }\cdot (x + 5)^{\frac{1}{3} }$ Definition of power
$f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }$ Derivative of a product of functions / Derivative of power function / Rule of chain / Result

(c) f(x) = (sin x - cos x) / (x² - 1)

f(x) = (sin x - cos x) / (x² - 1) Given
f'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)² Derivative of cosine / Derivative of sine / Derivative of power function / Derivative of a constant / Derivative of a division of functions / Result

(d) f(x) = 5ˣ · ㏒₅ x

f(x) = 5ˣ · ㏒₅ x Given
f'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)] Derivative of an exponential function / Derivative of a logarithmic function / Derivative of a product of functions / Result

(e) f(x) = (x⁻⁵ + √3)⁻⁹

f(x) = (x⁻⁵ + √3)⁻⁹ Given
f'(x) = - 9 · (x⁻⁵ + √3)⁻⁸ · (- 5) · x⁻⁶ Rule of chain / Derivative of sum of functions / Derivative of power function / Derivative of constant function
f'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶ Associative and commutative properties / Definition of multiplication / Result

(f) $f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}$

$f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}$ Given
$f'(x) = 7^{x\cdot\ln x} \cdot \ln 7 \cdot (\ln x + 1) + 7\cdot (x\cdot \ln x)^{6}\cdot (\ln x + 1)$ Rule of chain / Derivative of sum of functions / Derivative of multiplication of functions / Derivative of logarithmic functions / Derivative of potential functions
$f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}]$ Distributive property / Result

(g) $f(x) = \arccos^{2} x - \arctan (\sqrt{x})$

$f(x) = \arccos^{2} x - \arctan (\sqrt{x})$ Given
$f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) - \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2} \cdot x^{-\frac{1}{2} }\right)$ Derivative of the subtraction of functions / Derivative of arccosine / Derivative of arctangent / Rule of chain / Derivative of power functions / Result

(h) f(x) = ㏑ (sin x) + sin (㏑ x)

f(x) = ㏑ (sin x) + sin (㏑ x) Given
f'(x) = (1 / sin x) · cos x + cos (㏑ x) · (1 / x) Rule of chain / Derivative of sine / Derivative of natural logarithm /Derivative of addition of functions
f'(x) = cot x + cos (㏑ x) · (1 / x) cot x = cos x / sin x / Result

To learn more on derivatives: brainly.com/question/23847661

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7 0

2 years ago