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velikii [3]
3 years ago
9

A neon atom has 10 protons and 10 electrons. The 10 protons have a charge of +10 and the 10 electrons have a charge of −10 . No

other particles in the atom have a charge. What is the sum of the charges in the neon atom? Drag and drop the label on the number line to show the sum of the charges in the neon atom. please do now
Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0
10-10=0
10+10=20
Total charge:20
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A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su
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Answer:

After 1st year, the age distribution will be

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

x_1 = A \cdot x

x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = A \cdot x_1

x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

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