I'm only going to complete Part B. The other two are a bit easier and I believe you can do it! :D
Neighborhood A
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Year 1: 30 increased by 20% = 6 more homes.
Year 2: 36 increased by 20% = 7.2 more homes ... 7 more homes. You cannot round in these types of problems.
Year 3: 43 increased by 20% = 8.6 ... 8 more homes.
Year 4: 51 increased by 20% = 10.2 ... 10 more homes.
Year 5: 61 increased by 20% = 12.2 ... 12 more homes.
At the end of 5 years Neighborhood A will have 73 homes in total.
Neighborhood B
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Year 1: 45 +3 = 48
Year 2: 48 +3 = 51
Year 3: 51 +3 = 54
Year 4: 54 +3 = 57
Year 5: 57 +3= 60 homes
After 5 years Neighborhood B will have 60 homes.
Hope this helped! I will do Part A or Part C later if I have time and you still need assistance.
Hello!
We know that mike can bind 109 flowers per hour.
Lets create an equation to remember this.
<u>Mikes equation: </u>
<u>109x = y</u>
<u />
<x is representing per hour in this math problem>
We know that John can bind 116 flowers per hour, here is his equation.
<u>Johns equation:</u>
<u>116x = y</u>
<u />
Question: If they work together for 5 hours, how many flowers can they bind?
First, plug in the number five in both equations.
Second, solve the equation by multiplying.
Mikes:
109(5) = y
109 times 5 is 545
y = 545
Johns:
116(5) = y
116 times 5 is 580
y = 580
We want to know how many flowers can they bind if they work together.
This means we need to add the answers of the equations from both mike's and john's together.
545 + 580 = 1,125
The answer is 1,125
The answer is 13/4 3.25 is equal to 13/4
Answer:
B
Step-by-step explanation:
HOPE THIS HELPS
PLZZ MARK BRAINLIEST
Answer:
16.9
Step-by-step explanation:
