The length of a rectangle:
L = 2 W + 5
The perimeter:
P = 2 L + 2 W
130 = 2 · ( 2 W + 5 ) + 2 W
130 = 4 W + 10 + 2 W
130 - 10 = 6 W
120 = 6 W
W = 120 : 6
W = 20 in
L = 2 · 20 + 5
L = 40 + 5
L = 45 in.
Finally the area:
A = L · W
A = 20 · 45
A = 900 in²
Answer: New function is 
Step-by-step explanation:
- A dilation is a transformation that creates an image using a scale factor that has the exactly same shape as the original, but have a different size.
The given function : 
We know that any function y= f(x) will become y=k f(x) after dilation of k units on the x, where k= scale factor for dilation.
Here, the given scale factor = 2 i.e. k=2
Then, the new function will be :

Hence, the new function is 
Answer:
Yes, it is invertible
Step-by-step explanation:
We need to find in the matrix determinant is different from zero, since iif it is, that the matrix is invertible.
Let's use co-factor expansion to find the determinant of this 4x4 matrix, using the column that has more zeroes in it as the co-factor, so we reduce the number of determinant calculations for the obtained sub-matrices.We pick the first column for that since it has three zeros!
Then the determinant of this matrix becomes:
![4\,*Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] +0+0+0](https://tex.z-dn.net/?f=4%5C%2C%2ADet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%266%5C%5C0%263%268%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D%20%2B0%2B0%2B0)
And the determinant of these 3x3 matrix is very simple because most of the cross multiplications render zero:
![Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] =1 \,(3\,*\,1-0)+4\,(0-0)+6\,(0-0)=3](https://tex.z-dn.net/?f=Det%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%266%5C%5C0%263%268%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D%20%3D1%20%5C%2C%283%5C%2C%2A%5C%2C1-0%29%2B4%5C%2C%280-0%29%2B6%5C%2C%280-0%29%3D3)
Therefore, the Det of the initial matrix is : 4 * 3 = 12
and then the matrix is invertible
Answer:
Its plus 5
Step-by-step explanation:
8+5= 13
13+5= 18
18+5= 23
23+5= 28
Hope this helps ;)
First odd integer = x
second odd integer = x + 2
third odd integer = x + 4
sum of all three <span>consecutive odd integers:
x + x + 2 + x + 4
= 3x + 6
answer
3x + 6
hope it helps</span>