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Paraphin [41]
2 years ago
14

Select all the lines points that are on the line through (0,5) and (2,8)

Mathematics
1 answer:
bazaltina [42]2 years ago
7 0

Answer:

3x-2y-2=0

3x-2y+10=0

Step-by-step explanation:

let the slope of the line be 'm'

and also (x1,y1)=(0,5)

             (x2,y2)=(2,8)

we know the formula for finding slope m=\frac{Y2-Y1}{X2-X1}

m=\frac{8-5}{2-0} \\m=\frac{3}{2}

The equation of the line will be as,

(y-y1)=m(x-x1)\\(y-5)=\frac{3}{2}(x-0)\\ y-10=3x\\ 23x-2y+10=0\\(y-2)=\frac{3}{2}(x-2)\\ 2y-4=3x-6\\3x-2y-2=0

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  B. {16, 19, 20}

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<em>Additional comment</em>

The version of triangle inequality shown above ensures that a triangle will have non-zero area.

The alternative version of the triangle inequality uses ≥ instead of >. Triangles where a+b=c will look like a line segment--they will have zero area. Many authors disallow this case. (If it were allowed, then {8, 11, 19} would also be a "triangle.")

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