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3 years ago

55 and 45 find the the percent decrease round to the nearest whole number

Mathematics

1 answer:

Helen [10]3 years ago

5 0

Answer:

18.18%

Step-by-step explanation:

55-45=10

10/55=0.18

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Solve the two-step equation. 5.1 = –3x – 4.2

Tems11 [23]

$5.1 = -3x - 4.2$

$9.3=-3x$

$-3.1=x$

3 0

3 years ago

Read 2 more answers

Given the inequality below: 3x-y>4 Which is the graph of the solution set?

OLga [1]

Answer:

A shaded region below a dashed line (y <3x-4)

Step-by-step explanation:

For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.

Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.

In this case what we have here is an open region, as the graph below shows.

3x-y>4 =-y>4-3x∴y<3x-4

Setting a value for x

3x-4=0

3x=4

3x/3=4/3

x=4/3 (slope)

(4/3,0)

6 0

3 years ago

The solution is u = ?

Tpy6a [65]

Answer:

u = (b/hn)

Step-by-step explanation:

The inverse!!

3 0

2 years ago

An animal reserve has 20,000 elk. The population is increasing at a rate of 8% per year. This can be modeled by the function P(t

Scorpion4ik [409]

Answer:

The answer would be 31,737 elks.

Step-by-step explanation:

You would solve this by multiplying 1.08 by the power of 6 which equals 1.586874322944. You would then multiply this number by 20,000 which equals 31,737.4865 but since you can’t have .4865 of an elk the answer is just 31,737.

I hope this helps

8 0

3 years ago

2 tan 30° II 1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago