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Degger [83]
3 years ago
9

HELP PICTURE IS INCLUDEDWhat transformations were applied to ABCD to obtain A'B'C'D'?

Mathematics
1 answer:
Liula [17]3 years ago
4 0

In the figure ABCD is transformed to figure A'B'C'D'. It is Transformed from Quadrant 1 to quadrant 2 .That is point (x,y) is (-y,x) It is then moved up by 2 units.The figure ABCD is rotated counterclockwise and then translated up by 2 units to come to A'B'C'D'.

Option b Rotate 90 degrees counterclockwise then translate 2 units up is the right answer.



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Factor out the gcf then factor the remaining trinomial.
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Answer:

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Step-by-step explanation:

Given

18x² - 12x - 6 ← factor out 6 from each term

= 6(3x² - 2x - 1) ← factor the quadratic

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 3 × - 1 = - 3 and sum = - 2

The factors are - 3 and + 1

Use these factors to split the x- term

3x² - 3x + x - 1 ( factor the first/second and third/fourth terms )

= 3x(x - 1) + 1(x - 1) ← factor out (x - 1)

= (x - 1)(3x + 1)

Hence

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8 0
3 years ago
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Archy [21]
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3 years ago
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mr_godi [17]

Answer:

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4 0
3 years ago
Please solve number 11:(​
MrRa [10]

Answer:

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Step-by-step explanation:

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CP: cost price

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Step-by-step explanation:

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