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Degger [83]
3 years ago
9

HELP PICTURE IS INCLUDEDWhat transformations were applied to ABCD to obtain A'B'C'D'?

Mathematics
1 answer:
Liula [17]3 years ago
4 0

In the figure ABCD is transformed to figure A'B'C'D'. It is Transformed from Quadrant 1 to quadrant 2 .That is point (x,y) is (-y,x) It is then moved up by 2 units.The figure ABCD is rotated counterclockwise and then translated up by 2 units to come to A'B'C'D'.

Option b Rotate 90 degrees counterclockwise then translate 2 units up is the right answer.



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Find the surface area of a cylinder with a base radius of 2 yd and a height of 3 yd.
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Answer:

20 π

Step-by-step explanation:

The surface area of a cylinder is made up of 2 circles and its side.

To find the circles' areas, use the area formula for a circle: A = πr^2.

Since our radius is 2 yd, we can substitute r = 2 into this formula.

A = π2^2 = 4π

Now remember, this is only the area of once circle. Multiply 4π by 2 to get the area of both circles: 8π.

Now we need to find the surface area of the side.

If we flatten it out, we can see that the side is actually a curled up rectangle.

The length is the circumference of the circle and the width is the height of the cylinder.

To find the circumference, use the circumference formula for a circle: C = 2πr.

Substitute r = 2 into the formula.

C = 2π2 = 4π

Now that we know that the length is 4π, we can multiply the length by the width to find the area of the cylinder's side.

l = 4π

w = 3

A = lw = 4π * 3 = 12π

Finally, we can add the areas of the circles and the side to get the total surface area.

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Answer:

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