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2 years ago

9

Arthur tells you that he is thinking of an irrational number between 4 and 5, and he wants you to guess what it is. One possibil

ity you could guess is _____.
Options are:
√9
√20
4.5
√27

1 answer:

Naddika [18.5K]2 years ago

3 0

Answer:

$\sqrt{20}$

Step-by-step explanation:

Square root of 9 is 3

20 is 4.472135955

27 is 5.19615242271

4.5 is intantly wrong because it is rational.

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The extreme water slide forms a 20 angle with the tower it leans against 80 feet above the ground find the length of the slide x

GarryVolchara [31]

Answer:

85.1 ft

Step-by-step explanation:

The extreme water slide forms a 20 angle with the tower it leans against 80 feet above the ground find the length of the slide x

We solve using the Trigonometric function of Cosine

cos y = adjacent/hypotenuse

y = angle = 20°

Adjacent = 80 ft

Hypotenuse = ?

cos 20 = 80/Hypotenuse

Hypotenuse = 80/cos 20

x = 85.134221798 ft

Approximately = 85.1 ft

Length of the slide = 85.1 ft

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3 years ago

Gail, Lucas, and Joel are playing a number game where they must draw a card with a number on it. Then they compare the numbers o

Verdich [7]

Answer:

90

Step-by-step explanation:

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2 years ago

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Find the coordinates of the midpoint of the segment whose endpoints are R(9, 3) and S(-1, -9).

amm1812

Answer:

$(4, -3 )$

General Formulas and Concepts:

<u>Pre-Algebra I</u>

Order of Operations: BPEMDAS

<u>Algebra I</u>

Midpoint Formula: $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )$

Step-by-step explanation:

<u>Step 1: Define</u>

R (9, 3)

S (-1, -9)

<u>Step 2: Find midpoint</u>

Substitute: $(\frac{9-1}{2}, \frac{3-9}{2} )$
Subtract: $(\frac{8}{2}, \frac{-6}{2} )$
Divide: $(4, -3 )$

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2 years ago

What is the horizontal asymptote of the graph of f(x) = 4×5^x

Iteru [2.4K]

Answer:

The horizontal asymptote is y=0

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3 years ago

Hey could someone please help me with this really hard assignment is taking me forever. Thank you marking brainliest!

rewona [7]

Answer:

Exercise 1: The length of the unknown leg is 4 inches.

Exercise 3: The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4: Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

Step-by-step explanation:

Exercise 1:

Let suppose that triangle represented in the figure is a right triangle, the length of the missing leg is determined by Pythagorean Theorem:

$y = \sqrt{l^{2}-x^{2}}$ (1)

Where:

$l$ - Hypotenuse, in inches.

$x$ - Known leg, in inches.

$y$ - Unknown leg, in inches.

If we know that $l = 11\,in$ and $x = 10\,in$ , then the length of the unknown leg is:

$y = \sqrt{21}$

Since 4 is the least whole number closest to $\sqrt{21}$ , then we conclude that the length of the unknown leg is 4 inches.

Exercise 3:

The range of possible lengths for the missing side of the triangle is represented by the following simultaneous inequality:

$x + y > l > x-y$ (2)

Where:

$x$ - Greater side, in inches.

$y$ - Lesser side, in inches.

$l$ - Missing side, in inches.

If we know that $x = 8\,in$ and $y = 6\,in$ , then we have the following range of missing sides:

$14\,in > l > 2\,in$

The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4:

Let check each pair to determine possible constructions by means of the inequality used in Exercise 3:

(i) $x = 4\,in, y = 2\,in$

$6\,in>l>2\,in$

Possible choices: 5 inches.

(ii) $x = 5\,in, y = 2\,in$

$7\,in > l > 3\,in$

Possible choices: 4 inches, 6 inches.

(iii) $x = 6\,in, y = 2\,in$

$8\,in > l > 4\,in$

Possible choices: 5 inches, 6 inches.

(iv) $x = 10\,in, y = 2\,in$

$12\,in > l > 8\,in$

Possible choices: None.

(v) $x = 5\,in, y = 4\,in$

$9\,in > l > 1\,in$

Possible choices: 2 inches, 6 inches.

(vi) $x = 6\,in, y = 4\,in$

$10\,in > l > 2\,in$

Possible choices: 5 inches.

(vii) $x = 10\,in, y = 4\,in$

$14\,in > l > 6\,in$

Possible choices: None.

(viii) $x = 6\,in, y = 5\,in$

$11\,in > l > 1\,in$

Possible choices: 2 inches, 4 inches, 10 inches.

(ix) $x = 10\,in, y = 5\,in$

$15\,in > l > 5\,in$

Possible choices: 6 inches.

(x) $x = 10\,in, y = 6\,in$

$16\,in > l > 4\,in$

Possible choices: 5 inches.

Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

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2 years ago

Read 2 more answers