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3 years ago

Help! If anyone knows thanks

Mathematics

2 answers:

DerKrebs [107]3 years ago

6 0

A:
2t
t is the number of toys

b:
(p+12)/16
p is the price

Brums [2.3K]3 years ago

6 0

A)
x is number of toys
the product of 2 and number of toys is 2x
b)
x is the price
(x + 12)/16

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The area of a rectangle is 479.4 square feet. The width of the rectangle is 17 feet.

Katarina [22]

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2 years ago

The largest set of x values satisfying

velikii [3]

Answer:

If $p\ge -\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

Step-by-step explanation:

Solve two inequalities for x.

1. $2,018x-p$

Separate terms with x and without x into two sides:

$2,018x-2,020x$

Multiply by -1:

$2x>-2p\\ \\x>-p$

2. $7x+3p$

Separate terms with x and without x into two sides:

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Multiply by -1:

$3x>2+3p\\ \\x>\dfrac{2}{3}+p$

Find the largest set of x values satisfying both inequalities:

$x>-p\\ \\x>\dfrac{2}{3}+p$

$-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p$

then $x>-p$ and $mn=-p=p\cdot (-1),\ m+n=p-1.$ In this case both m and n are negative.

If $p>-\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

If $p=-\dfrac{1}{3},$ then $x>\dfrac{1}{3}$ and $mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}$

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3 years ago

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Serggg [28]

Answer:

Step-by-step explanation:

7 0

3 years ago

Can someone help i wil mark branliest to anyone who gets this right

Elan Coil [88]

Answer:

48.16

167.68

Step-by-step explanation:

New value =

36 - Percentage decrease =

36 - (14% × 36) =

36 - 14% × 36 =

(1 - 14%) × 36 =

(100% - 14%) × 36 =

86% × 36 =

86 ÷ 100 × 36 =

86 × 36 ÷ 100 =

3,096 ÷ 100 =

30.96

New value =

262 - Percentage decrease =

262 - (36% × 262) =

262 - 36% × 262 =

(1 - 36%) × 262 =

(100% - 36%) × 262 =

64% × 262 =

64 ÷ 100 × 262 =

64 × 262 ÷ 100 =

16,768 ÷ 100 =

167.68

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3 years ago

Which statement is true about the box plots? A number line goes from 0 to 13. Marc's class's whiskers range from 1 to 10, and th

kondor19780726 [428]

Answer:

The answer is D.

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Therefore, the ranges for the box plots are the same, but their interquartile ranges are different.

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3 years ago

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