Question

Christines rectangular bedroom has a perimeter of 44 feet. The length of her bedroom is 2 more than the width. What are the dimensions of her room?

Answer 1

Answer:

Length = 12 feet, Width = 10 feet

Step-by-step explanation:

Let the length of the bedroom be 'x' ft and the width of the bedroom be 'y' ft.

We know that the perimeter of a rectangle is given by,

$P=2(\text {length}+\text {width})$

$P=2(x+y)$

It is given that, the length of the bedroom is 2 more than the width, so,

$x=y+2$

Putting the values in the equation of perimeter we get,

$44=2((y+2)+y)$

$44=2(2y+2)$

$\frac{44}{2}=2y+2$

$22=2y+2$

$2y=22-2$

$y=\frac{20}{2}=10$

Therefore, $x=y+2=10+2=12$

Hence, the length of the bedroom is 12 feet and the width of the bedroom is 10 feet.