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Rufina [12.5K]
3 years ago
15

1 1/3 divided by 3 + 1/3

Mathematics
1 answer:
Phantasy [73]3 years ago
3 0
The first step to solve this problem is to convert the first mixed number to an improper fraction.
\frac{4}{3} ÷ 3 + \frac{1}{3}
Dividing is equivalent to multiplying with the reciprocal value,, so next you will need to change the signs.
\frac{4}{3} x \frac{1}{3} + \frac{1}{3}
Multiply the fractions
\frac{4}{9} + \frac{1}{3}
Finally,, add the two fractions together to get your final answer
\frac{7}{9}
This means that the correct answer to your question is \frac{7}{9} .
Let me know if you have any further questions
:)
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Need Help 20 points plz.
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Answer:

  the correct choices are shown

Step-by-step explanation:

<u>Statement</u> . . . . . <u>Reason</u>

1. c ║ d; ∠4 = ∠5 . . . . . Given

2. ∠4 = ∠7 . . . . . Alternate interior angles are equal

3. ∠5 = ∠8 . . . . . Vertical angles are equal

4. ∠7 = ∠8 . . . . . Substitution

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2 years ago
Francine has a picture that is 5/2 its width. She wants to enlarge the picture to have an area of 490 in2. What will the dimensi
serg [7]

Answer:

Length = 2w

Width= w

2w times w= 241

2W^2=241

Divide by 2

W-^2=121

Sq rt each side

W-= 11 cuz 11 times 11=121

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Today everything at a store is on sale The store offers a 20% discount The regular price of a tshirt is 18$ what is the discount
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3 years ago
1/4 cup equals how many pounds?
Leno4ka [110]

1/4 cup equals 0.25 lbs.

6 0
3 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
Kruka [31]

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of type A paint

x2 = sample mean of type B paint

s1 = sample standard deviation type A paint

s2 = sample standard for type B paint

n1 = number of samples of type A paint

n2 = number of samples of type B paint

From the information given,

x1 = 75.7

s1 = 4.5

n1 = 11

x2 = 64.3

s2 = 5.1

n2 = 9

x1 - x2 = 75.7 - 64.3 = 11.4

√(s1²/n1 + s2²/n2) = √(4.5²/11 + 5.1²/9) = √4.709

Degree of freedom = (n1 - 1) + (n2 - 1)

df = (11 - 1) + (9 - 1) = 18

For the 98% confidence interval, the z score from the t distribution table is 2.552

Margin of error = 2.552√4.709 = 5.55

The upper boundary for the confidence interval is

11.4 + 5.55 = 16.95 hours

The lower boundary for the confidence interval is

11.4 - 5.55 = 5.85 hours

The correct option is

B. 5.85 hrs < μ1 - μ2 < 16.95 hrs

4 0
3 years ago
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