E - English homework, M - Math homework;
M + E ≤ 2 hours
M = 2 E
2 E + E ≤ 2 hours
3 E ≤ 2 hours = 120 minutes
E ≤ 120 : 3
E ≤ 40 minutes
Answer:
The student will be able to finish his English homework in less or equal to 40 minutes.
Answer:
$0.60
Step-by-step explanation:
2 • 4 = 6
6 • 0.10 = 0.60
Answer:
50
Step-by-step explanation:
The perimeter of a Triangle is the sum of it's 3 sides.
We are given two sides here which is side length 5.6 and a side of length 19.7
Let's us represent the third side as x
Therefore
x + 19.7 + 5.6 = Perimeter of the triangle
We would have this equation
But it is important to know that every side of a triangle must be less than the sum of the other two sides, hence
x < 19.7 + 5.6
x < 25.3
Adding 25.3 to both sides to make the left side equal to the perimeter
perimeter = x+25.3 < 25.3 + 25.3 = 50.6
Therefore, 50.6 is the smallest whole number that is larger than the perimeter of the triangle in the question above.
Therefore, the biggest whole number smaller than the perimeter of the above triangle is 50
Answer:
For the sampling distribution of the sample proportion for a sample of size 50, the mean is 0.061 and the standard deviation is 0.034.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean
and standard deviation 
In this question:

So
Mean:

Standard deviation:

For the sampling distribution of the sample proportion for a sample of size 50, the mean is 0.061 and the standard deviation is 0.034.
Answer:
Step-by-step explanation
Let the number be y
y doubled = y×2=2y
2y increases by 3 = 2y+3=
2y +3 is more than 6 but less than 20
2y+3 > 6
2y+3< 20
Solve for y
2y>6-3
y>3/2
2y+3<20
2y<20-3
2y<17
y<17/2