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riadik2000 [5.3K]
3 years ago
12

Find the distance between the two points. ​(negative 1​,7​) and ​(159​,43​)

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0
To find distance you use the distance formula

The answer is 163.8

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What is equivalent to 25c+15
aniked [119]

The Answer is: 5 (5c+3)

Step-by-step explanation:

8 0
3 years ago
Using the digits 0, 1, 2, ...8, 9, determine how many 4-digit numbers can be constructed according to the following criteria.
Alexxandr [17]

Answer:

2000

Step-by-step explanation:

Since the number must be odd, it can have either 1, 3, 5, 7 or 9 in its one's place.

With a 4-digit number starting with 6, any of these digits can be in the one's place and it will still be greater than 6,000.

For the one's place, since we can choose from 5 digits, we have ⁵P₁. In the thousands place, we have one digit which is 6. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively.

So, the total number of 4 digit odd numbers greater than 6000 starting with 6 are 1 × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 1 × 10 × 10 × 5 = 500 numbers.

For the thousands place, we are left with the digits 7, 8 and 9. So, to arrange these 3 digits in the thousands place, we have ³P₁. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively. For the one's place, since we can choose from 5 digits, we have ⁵P₁.

So, the total number of 4 digit odd numbers greater than 6000 starting with 7, 8 or 9 are  ³P₁ × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 3 × 10 × 10 × 5 = 1500 numbers.

So, the total number of 4-digit numbers greater than 6000 that can be constructed is 500 + 1500 = 2000 numbers.

5 0
3 years ago
Which of the following would be the correct form of the equation 10t² - 29t = -10 to be able to solve using the zero product pro
zhannawk [14.2K]

It’s the first one t(10t-29)=-10

8 0
3 years ago
The length and width of a rectangle must have a sum of 66. find the dimensions of the rectangle that will have the maximum area
lawyer [7]
Are there any answer choices

3 0
4 years ago
The four points (−2, 5), (−2, −1), (6, −1), and (3, 5) are the vertices of a polygon. What is the area, in square units, of this
crimeas [40]
Look at the picture.

The polygon is a right-angled trapezoid.

The area is:
A=\frac{a+b}{2} \times h

The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.

A=\frac{8+5}{2} \times 6=\frac{13}{2} \times 6=13 \times 3=39

The area is 39 square units.

5 0
3 years ago
Read 2 more answers
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