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3 years ago

6

G(x)=(x^2+1)(3x-5) what is the value of g(4)?

1 answer:

MAVERICK [17]3 years ago

5 0

g(x) = x^2 + 1(3x - 5)

<em><u>Replace all x's with 4.</u></em>

g(4) = 4^2 + 1(3 * 4 - 5)

g(4) = 16 + 1(12 - 5)

g(4) = 17(7)

g(4) = 119 (This is your answer.)

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