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elena-s [515]
2 years ago
15

A recent study focused on the number of times men and women send a Twitter message in a day. The information is summarized below

.
Men Sample size-25 Sample mean-20 Population standard deviation-5
Women Sample size-30 Sample mean-30 Population standard deviation-10
At the .01 significance level, is there a difference in the mean number of times men and women send a Twitter message in a day? What is the value of the test statistic for this hypothesis test?
1. 2.668
2. 2.672
3. 2.58
4. 2.40
Mathematics
1 answer:
jok3333 [9.3K]2 years ago
7 0

Answer:

The value of the test statistic = 2.58

Test statistic Z = - 4.805

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

There is  significant difference between in the mean number of times men and women send a Twitter message in a day

Step-by-step explanation:

Step(i):-

Sample size of men  n₁ = 25

mean of the first sample x₁⁻ = 20

Standard deviation of the first sample σ₁ = 5

Sample size of women n₂ = 30

mean of the second sample x₂⁻ = 30

Standard deviation of the first sample σ₂ = 10

Level of significance ∝= 0.01

<u>Step(ii)</u>:-

Null Hypothesis : H₀: There is no significant difference between in the mean number of times men and women send a Twitter message in a day

Alternative Hypothesis :H₁:There is  significant difference between in the mean number of times men and women send a Twitter message in a day

Test statistic

Z = \frac{x^{-} _{1} - x^{-} _{2} }{\sqrt{\frac{S.D_{1} ^{2} }{n_{1} }+\frac{ S.D_{2} ^{2}}{n_{2} }  } }

Z = \frac{20 - 30 }{\sqrt{\frac{(5)^{2}  }{25 }+\frac{ (10)^{2}  }{ 30}  } }

Z =  \frac{-10}{2.081} = - 4.805

The value of the test statistic = 2.58 C

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

<u>Conclusion:</u>-

There is  significant difference between in the mean number of times men and women send a Twitter message in a day

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Step-by-step explanation:

We are given that the 55 randomly selected political science classes assigned an average of 19.6 pages of essay writing for the course. The standard deviation for these 55 classes was 4.8 pages.

The 50 randomly selected history classes assigned an average of 20.2 pages of essay writing for the course. The standard deviation for these 50 classes was 3.3 pages.

<em>Let </em>\mu_1<em> = mean writing required by political science classes</em>

<em />\mu_2<em> = mean writing required by history classes</em>

SO, Null Hypothesis, H_0 : \mu_1-\mu_2\geq0  or  \mu_1\geq \mu_2    {means that political science classes require more or equal writing than history classes}

Alternate Hypothesis, H_A : \mu_1-\mu_2  or  \mu_1   {means that political science classes require less writing than history classes}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                     T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample average writing for political science course= 19.6 pages

\bar X_2 = sample average writing for history course= 20.2 pages

s_1 = sample standard deviation for political science classes = 4.8 pages

s_2 = sample standard deviation for history classes = 3.3 pages

n_1 = sample of selected political science classes = 55

n_2 = sample of selected history classes = 50

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }  =  \sqrt{\frac{(55-1)\times 4.8^{2}+(50-1)\times 3.3^{2}  }{55+50-2} }  = 4.154

So, <u><em>the test statistics</em></u>  =  \frac{(19.6-20.2)-(0)}{4.154 \times \sqrt{\frac{1}{55}+\frac{1}{50}  } }  ~  t_1_0_3

                                     =  -0.739

<em>Now at 0.01 significance level, the t table gives critical value of -2.367 at 103 degree of freedom for left-tailed test. Since our test statistics is more than the critical value of t as -0.739 > -2.367, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that political science classes require more or equal writing than history classes.

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