What is the rate between 78 miles and 3 gallons of gas

a) Answer: 0.2 

consider the 4 refrigerators that waschosen out of the 6. There are 6*5*4*3 ways to choose these refrigerators (not 6choose4, since refrigerators are distinguishable). Therefore the denominator of our probability is 360.

The numerator is a bit harder. Consider the first 3 refrigerators that was chosen. 2 were good, 1 was bad. There are 3choose1 = 3 places that the bad refrigerator can go. In each of these places, we count the number of ways to pick these 3 out of the 6. Since one is good, there are 4 ways (b/c there are 4 good refrigerators) to select the first. Another is also good, so the number of ways becomes 4*3. The last is bad, and there are 2 bad ones, so the number of ways to select these 3 becomes 4*3*2. Do not be confused by the fact that I ordered the above, this is taken care of by multiplying by the 3choose1 from above. Think of it like 4*3*2 + 4*2*3 + 2*4*3. Regardless, there is only one choice for the 4th refrigerator: bad. Thus the number of ways of being able to find the last bad fridge on the 4th test is 3*4*3*2 = 72.

The probability is then 72/360 = 0.2

I did the same method for the probability of searching the last bad fridge on the nth trial, and they all added to 1, so I'm pretty sure this is right.

b) Answer: 0.4

This probability is equal to:
P(find on 2nd) + P(find on 3rd) + P(find on 4th)

You know the third term, and the first two you can find in the same way as I did above. They are 0.06666... and 0.1333333...

c) Answer: 0.5

This is P(find on 3rd) + P(find on 4th)

You know that of the 4 refrigerators left, 3 are good and 1 is bad. So, P(3) = 1/4, because there is a 1 in 4 chance that you choose the bad one right away

P(4) = 3/4 * 1/3 = 0.5, since there is a 3 in 4 shot you select a good one, then a 1 in 3 that you select a bad one.

So P(3) + P(4) = 0.5

4 0

3 years ago

Is a triangle with sides of length 6ft, 21 ft, 23 ft a right triangle

Rainbow [258]

Try the Pythagorean theorem, $a^{2} + b^{2}= c^{2}$ . Does $6^{2} + 21^{2} = 23^{2}$ ? If it does, you have yourself a right triangle. If it doesn't, then it isn't a right triangle.