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kogti [31]
3 years ago
13

suppose you work at a job where your pay varies directly as the number of hours you work.Your pay for 7.5 hours is $45. Find you

r pay for working 30 hours.
Mathematics
2 answers:
Maksim231197 [3]3 years ago
4 0
You will get paid $180 because there are 4, 7.5 hours in 30 hours so you multiply $45*4 and you get $180

Please mark brainliest
dedylja [7]3 years ago
3 0

Answer:

$180.

Step-by-step explanation:

Given: Pay for 7.5 hours is $45.

To find: Pay for working 30 hours.

Solution: It is given that pay for 7.5 hours is $45. In order to find the pay for  hours we first need to find the pay for 1 hour, then we are able to find the pay for 30 hours as well.

Now, pay for 7.5 hours=45

pay for 1 hour =\frac{45}{7.5}=6

So, for 1 hour the pay is $6.

Now, to find the pay for 30 hours, we need to multiply the pay per hour by 30.

Therefore, pay for 30 hours =30\times6=180

Hence, pay for working 30 hours is $180.

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4x+100 6x+216 find x
Lemur [1.5K]

Answer:

4x=100+6x=216=

Step-by-step explanation:

100+216=316 and 4x+6x= 10

316/10 = 31.6

6 0
3 years ago
7. A fish tank hold 100 gallons of water and is losing water at a rate of 1 gallons per hour. A second fish tank
djverab [1.8K]

Answer:

B

Step-by-step explanation:

the first fish tank has 100 gallons of water and 1 gallon is removed every hour which makes 100-h

the second tank has 40 gallons in it and 2 gallons are added every hour which makes 40+2h

after 20 hours the second tank will have more gallons than the first tank

this means that 40+2h would be greater than 100-h since it's also asking you "After how many hours will the first tank  have less water than the second?"

4 0
3 years ago
Refer to the photo :D
OlgaM077 [116]

well, we know the ceiling is 6+2/3 high, and Eduardo has 4+1/2 yards only, how much more does he need, well, is simply their difference, let's firstly convert the mixed fractions to improper fractions and then subtract.

\stackrel{mixed}{6\frac{2}{3}}\implies \cfrac{6\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{20}{3}} ~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{20}{3}-\cfrac{9}{2}\implies \stackrel{using ~~\stackrel{LCD}{6}}{\cfrac{(2\cdot 20)-(3\cdot 9)}{6}}\implies \cfrac{40-27}{6}\implies \cfrac{13}{6}\implies\blacktriangleright 2\frac{1}{6} \blacktriangleleft

4 0
2 years ago
If a and B are the zeros of the quadratic polynomial f(x) = x2- 5x + 4 find the value of 1/a+1/b-2ab
bearhunter [10]

Answer:

<h2>-27/4</h2>

Step-by-step explanation:

Given the quadratic polynomial given as g(x) = x²- 5x + 4, the zeros of the quadratic polynomial occurs at g(x) = 0 such that x²- 5x + 4 = 0.

Factorizing the resulting equation to get the roots

x²- 5x + 4 = 0

(x²- x)-(4 x + 4) = 0

x(x-1)-4(x-1) = 0

(x-1)(x-4) = 0

x-1 = 0 and x-4 = 0

x = 1 and x = 4

Since a and b are known to be the root then we can say a = 1 and b =4

Substituting the given values into the equation  1/a+1/b-2 ab , we will have;

= 1/1 + 1/4 - 2*1*4

= 1 + 1/4 - 8

= 5/4 - 8

Find the Lowest common multiple

= (5-32)/4

= -27/4

<em>Hence the required value is -27/4</em>

5 0
3 years ago
Mr. and mrs.storey drive 3200 miles in all during their vacation. mr.storey drove 3 times as many miles as mrs.storey how many m
vaieri [72.5K]
This can be solve by establishing equations.
let x be the miles mrs. storey drove
y be the miles mr storey drovee
 
the first equation is
y = 3x

second equation
x + y = 3200
then substitute equation 1

x + 3x = 3200
4x = 3200
x = 800 miles mrs storey drove
y = 3x = 2400 miles mr storey drove
5 0
3 years ago
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