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IRISSAK [1]
3 years ago
12

Solve the following equation M-6 3 —— = —- 8 2

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0
By changing the denominator to 8 you will get m-6/8 = 12/8

remove the denominators
m - 6 = 12
m = 12 + 6
= 18
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20 POINTS!!! PLEASE HELP
Katena32 [7]

The logarithm of 10 to base 10 is 1

<h3>How to determine the logarithm?</h3>

The given parameters are:

Base = 10

Number = 10

So, the expression is:

\log_{10}10

As a general rule;

\log_{a}a = 1

The above means that;

When the base and the number are the same, the logarithm is 1

So, we have:

\log_{10}10 = 1

Hence, the logarithmic value is 1

Read more about logarithm at:

brainly.com/question/20785664

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3 0
1 year ago
A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
RoseWind [281]

Answer:

There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).

The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

4 0
3 years ago
In a game of chance, the probability of winning a $50 is 40% and the probability of losing a $50 prize is 60%. what is the expec
melamori03 [73]
To calculate expected value,
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So the answer is $-10
4 0
3 years ago
Write 93 11/16 as a decimal
drek231 [11]
93 11/16 written as a decimal is 93.6875. Rounded it is approximately 93.7

I hope this helps:)
4 0
3 years ago
HELP ASAP. Dilation scale=2, center (5,4) <br> Graph the new points
frosja888 [35]

Answer:

3.5

Step-by-step explanation:

5 0
2 years ago
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