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3 years ago

Arlette set her watch 5 seconds behind, and it falls behind another 1 second every day. How

Mathematics

1 answer:

VLD [36.1K]3 years ago

7 0

So we know that it's already 5 seconds behind on the first day.

On the second day, it's 6 seconds behind.

And on the third, it's 7 seconds behind.

And so on...

The difference between the day, and the seconds is 4.

This means, that whatever day it is (say 17 for example), and add 4, will come to how many seconds behind (17 + 4 = 21 in this case)!

So we subtract 29 by 4, to find the day:

29 - 4 = 25 days.

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The pyramid shown has a square base that is 18 inches on each side. The slant height is 16 inches. What is the surface area of t

Alik [6]

The answer is 28sqinches Why The Surface Area of a pyramid is A=L×W×Have since the base is l×with combined it's now SA=BA×H
SA=18×16
SA=288sqinches.

4 0

3 years ago

PLZZZZZZZ HELLPPPP MEEEE I HAVE A HEADACHE WITH THIS<br><br> Find the measure of angle b.

Salsk061 [2.6K]

31) 27
32) 75
33) 74
34) 90 (because it’s a right angle and adds up to 180)

4 0

3 years ago

Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 104 miles in the same time that Dana travels 96 miles. If

Yanka [14]

Answer: Chuck's travel at a rate of 52mph

Step-by-step explanation:

For Chuck's trip:

D=RT

104= (R+4)T

T= 104 / (R+4)

For Dana's trip:

96 = RT

T= 96/R

Set both equation for Chuck's and Dana together

104/(R+4) =96/R

Then we cross multiply

96(R+4) = 104R

96R + 384 = 104R

104R - 96R = 384

8R = 384

To get R, divide both side by 8

8R/8 = 384/8

R= 48mph

This means Dana's speed is 48mph

Chuck's speed will be: 48mph+4mph = 52mph

3 0

3 years ago

Find three consecutive even integers whose sum is 252

Naily [24]

82, 84, and 86 are your three consecutive even integers.

8 0

3 years ago

The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c

Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so $p = \frac{2}{20} = 0.1$ .

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487$

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0

4 years ago