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Katen [24]
3 years ago
9

A developer wants to enclose a rectangular grassy lot that borders a city street for parking. if the developer has 256 feet of f

encing and does not fence the side along the​ street, what is the largest area that can be​ enclosed?
Mathematics
1 answer:
Elanso [62]3 years ago
7 0

Let the lenght perpendicular to street = x

Means lenght two sides will be x and x

Another side of retangle will be = 256 - 2x

Area of rectangle will be= A = x * (256-2x) = 256 x - 2 x^2

For maximum area, dA/dx = 0

d/dx (256 x - 2 x^2) = 0

256 - 4 x = 0

4 x = 256

x = 64 feet

Means one side is 64 feet

Another side will be = 256 - 2 * 64 = 128

Now we have two sides of rectangle 64 and 128

Area = 128 * 64 = 8192 square feet : Answer

Hope it will help :)

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Tju [1.3M]

Answer:

6x-5y-40 = 0

Step-by-step explanation:

y-(-2)=6/5(x-5)

5(y+2)= 6(x-5)

5y+10 =6x-30

6x-5y-40 = 0

6x-5y-40 = 0 is the answer

5 0
2 years ago
Jennifer receives $100 and puts it into her savings account. She adds $0.25 to the account each day for a number of days, d, aft
Alona [7]

This would be A because $100 is the initial amount, and you are adding the amount that arises after (d) days. Since you are adding, it will be the sum. B says product, so you can rule it out. D says difference, so you can rule that out as well. C would be adding the days, not the amount earned each day.

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3 years ago
If (2 − 3i) + (x + yi) = 6, what is x + yi?
Soloha48 [4]

(2 − 3i) + (x + yi) = 6

We add the left hand side

(2+x) + (-3+y)i = 6

6 can be written in a+ib

6 can be written as 6 + 0i

(2+x) + (-3+y)i = 6 +0i

Now we frame 2 equations

2 + x= 6

-3 + y =0

Solve the first equation

2 + x = 6

Subtract 2 from both sides

x = 4

solve the second equation

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Add 3 on both sides

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So x+yi is 4+3i

7 0
3 years ago
Read 2 more answers
Solve this and help me plsss​
alexandr402 [8]

Answer:

x = 2

Step-by-step explanation:

(x² logₓ27) log₉x = x + 4

Use change of base formula.

x² (log 27 / log x) (log x / log 9) = x + 4

Simplify.

x² (log 27 / log 9) = x + 4

x² (log 3³ / log 3²) = x + 4

x² (3 log 3 / (2 log 3)) = x + 4

x² (3 / 2) = x + 4

3x² = 2x + 8

3x² − 2x − 8 = 0

(x − 2) (3x + 4) = 0

x = 2 or -4/3

Since x > 0, x = 2.

8 0
3 years ago
Junior has 4 skittles in a bag, one is red, one is blue, one is green, and one is yellow. Junior takes a skittle out and eats it
forsale [732]

Answer:

The tree diagram is shown below.

Step-by-step explanation:

The color of the four skittles Junior had in his bag are:

S = {red (R), blue (B), green (G) and yellow (Y)}

It is provided that Junior takes a skittle out and eats it and then takes another skittle from the bag.

So, Junior has four options for the first draw, i.e. {R, B, G and Y}.

Then three options for the second draw. But the second draw is dependent on the first draw.

  • If Junior ate the red skittle first, then the second skittle could be any of the three, (B, G and Y).
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  • If Junior ate the green skittle first, then the second skittle could be any of the three, (R, B and Y).
  • If Junior ate the yellow skittle first, then the second skittle could be any of the three, (R, B and G).

Consider the tree diagram below to better understand the information above.

6 0
2 years ago
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