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3 years ago

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at 7:00 pm the temperature is 10°F for the next 4 hours, the temperature decreases by 3°F each hour. what is the temperature at

11:00 pm write the expression then solve

1 answer:

xxTIMURxx [149]3 years ago

5 0

-2 degrees because 4 times -3 is -12 and 10-12 is -2

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. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$

and the line should pass throught S as well, i.e $(5,-4)$ . Plugging all these values in the equation we'll get.

$(y - (-4)) = \dfrac{13}{16}(x-5)$

$y +4 = \dfrac{13x}{16}-\dfrac{65}{16}$

$y = \dfrac{13x}{16}-\dfrac{65}{16}-4$

$y=\dfrac{13x}{16}-\dfrac{129}{16}$

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for $T(-8,12)$

$(y - y_1) = m(x-x_1)$

$(y -12) = \dfrac{13}{16}(x+8)$

$y = \dfrac{13x}{16}+ \dfrac{104}{16}+12$

$y = \dfrac{13x}{16}+ \dfrac{37}{2}$

this is the equation of the line that is perpendicular to ST and passes through T

7 0

3 years ago

The circle graph shows the result of a survey. In what way is this graph misleading? Explain.

Rashid [163]

Step-by-step explanation:

because the total sum of each percent is 90%

and it must be 100% as it is a full circle

6 0

2 years ago

To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in

lukranit [14]

Answer: $\dfrac{26}{27}$

Step-by-step explanation:

Given : To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in appearance.

Proportion of success : $p=\dfrac{6}{9}=\dfrac{2}{3}$

Sample size taken by customs oﬃcial : n= 3

Let x be a binomial variable that represents the tablets in the bottle.

Using Binomial probability formula :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

The probability that the traveler will be arrested for illegal possession of narcotics = $P(x\geq1)=1-P(x=0)$

$1-^3C_0(\dfrac{2}{3})^0(1-\dfrac{2}{3})^3\\\\=1-(1)(1)(\dfrac{1}{3})^3\ [\becuase ^nC_0=1]\\\\=1-\dfrac{1}{27}=\dfrac{26}{27}$

Hence, the probability that the traveler will be arrested for illegal possession of narcotics = $\dfrac{26}{27}$

8 0

3 years ago

F(x)=-x^2+3 find f(-2)

Black_prince [1.1K]

Answer:

f(-2) = -1

Step-by-step explanation:

f(x) = -x^2 + 3

f(-2) means when x is -2

Shown in the graph below, the point of solution is: (-2,-1), so when x is -2 y is -1

8 0

3 years ago

SOMEONE PLEASE HELP ME WITH THESE 3 MATH QUESTIONS!!!!!

Len [333]

Look at the pictures (examples)

m∠1 = m∠6 → answer: none

m∠2 = m∠3 → answer: none

m∠2 = m∠C → answer: none

7 0

3 years ago