3(z+2)
= 3z+ 3*2 (distributive property)
= 3z+ 6
The final answer is 3z+6~
12w - 13 - 11w + 24 = 77
combine like terms
w + 11 = 77
subtract 11 from both sides
w = 66
Morse code is essentially the same as binary. That is, there are two "digits", a dot or a dash.
There are 26 letters in the English alphabet. Clearly, we can't just use one dot or dash, since that could only encode 2 letters at the most. We can't use two symbols because that could only encode 4 letters at the most. Similarly, 3 symbols means
letters at most.
We have to select the smallest power of 2 that exceeds or is equal to 26. In this case,
, so we would have to use up to 5 symbols to encode each letter in the alphabet.
Answer:
A. m^2+7m+10=0
Step-by-step explanation:
This is a problem in pattern matching, and in substituting a variable for a pattern.
(x^2+3)^2 +7x^2 +21 = -10 . . . . . . given
(x^2 +3)^2 +7(x^2 +3) = -10 . . . . . factor the last two terms
m^2 +7m = -10 . . . . . . . . . . . . subsitute m for x^2 +3
m^2 +7m +10 = 0 . . . . . . . . add 10 to both sides; matches A