Answer:
Step-by-step explanation:
The given data set is:
Week 1: 600
Week 2: 300
Week 3: 500
Week 4: 900
The following are the steps to find the standard deviation:
Step 1. Jim enters the data and calculates the average or mean.
Step 2. Jim calculates the deviation from the mean by subtracting the mean from each value.
Data value (x) 
600 25
300 -275
500 -75
900 325
Step 3. Jim squares each deviation to remove negative signs.
Data value (x) 
600 625
300 75625
500 5625
900 105625
Step 4. Jim sums the squares of each deviation and divides by the count for the variance.
Step 5.Jim takes the square root of the variance to find the standard deviation.
The answer is only 0 and 3.9
If this helped mark me brainliest
Answer:
Step-by-step explanation:
In the associative property of multiplication, the product of the multiplication of 3 or more numbers is the same irrespective of how they are grouped. This means that irrespective of the bracket or which number comes first, the product will always be the same.
From the given scenarios, the pair of expressions that are equivalent using the Associative Property of Multiplication are
B 6(4a ⋅ 2) = (4a ⋅ 2) ⋅ 6
C 6(4a ⋅ 2) = 6 ⋅ 4a ⋅ 2
D6(4a ⋅ 2) = (6 ⋅ 4a) ⋅ 2
The results are the same irrespective of the arrangement of the numbers.
Answer:
it's easy hope I could help
Step-by-step explanation:
the -3 goes on the y line
4/3 goes on the positive side so on the y and x
Answer:
$8(x + 10)
Step-by-step explanation:
The expression $8x + $80 has two terms. They are $8x and $80.
When you factor an expression, you are looking for numbers that every term in the expression can divide by (and give a whole number).
Just by looking at the terms, you see they both have $ you can factor out. They can both also be divided by 8. This is called taking out a common factor.
$8x + $80 Take out the common factor
= ($8x) / $8 + ($80) / $8
= $8(x + 10) The common factor goes outside the terms' bracket
This expression can't be factored more because there are no common factors. The binomial also doesn't have square numbers for example, which might make a case where you need to factor further with different methods.
