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3 years ago

Simplify the expression

Mathematics

1 answer:

krek1111 [17]3 years ago

3 0

170-9*(6*2*4)=170-9*48=170-432= -262

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Which figure is the image produced by applying the composition T 0,3 o R0,90 to figure R?

Lyrx [107]

We are given original image R.

It is being translated by (0,3) first and then rotated by a positive angle 90 degrees.

Translation by (0,3) represents (x,y) --> (x, y+3) rule.

Positive 90 degree rotation represents, counterclockwise rotation.

The rule for counterclockwise rotation is (x,y) --> (-y,x).

Therefore, final rule for would be

(x,y) --> ( -y,x+3 )

Let us take a coordinate of R on y-axis as (0,-4).

Now if we apply rule (x,y) --> ( -y,x+3 ) we get

(0,-4) --> (-(-4), 0+3) = (4,3).

Let us check the figure with coordinate (4,3).

We can clearly see that Figure H has transformed coordinate (4,3).

<h3>Therefore, correct option is first option A. figure H.</h3>

8 0

3 years ago

2n +5)=2<br> Help me please

Kobotan [32]

Answer:

-1.5

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

38=x+10+9-3<br>I don't get this question

Lilit [14]

Answer:

so is that all it says, if its not thats not a question because its already answered

Step-by-step explanation:

4 0

3 years ago

What is the value of X?

algol [13]

Answer:

x = 3

Step-by-step explanation:

ΔABC is 45 45 90 right triangle

The ratio of leg: hypo = a : a√2

Given: hypo AC = 6√2; so AB = BC = 6

ΔBCD is 30 60 90 right triangle

The ratio of short leg : long leg : hypo = x : x√3 : 2x

Hypo. BC = 6 = 2 (3)

So short leg BD = x = 3

7 0

2 years ago

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

8 0

3 years ago