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Afina-wow [57]
4 years ago
3

Each side of the regular hexagon below has the same measure. A hexagon with side lengths of 2.5 feet. If a model of the hexagon

is made by using a scale factor of 6, which applies to the model? Select two options.. The model represents a reduction. Each side of the model is 15 feet long. The model is proportional to the original hexagon. One side of the model can be 8.5 feet. The scale factor is divided by 2.5 to get the dimensions of the model.
Mathematics
2 answers:
Natalija [7]4 years ago
6 0

Answer:

b.) each side of the model is 15 feet long

c.) the model is proportional to the original hexagon

Step-by-step explanation:

A hexagon with side lengths of 2.5 feet. If a model of the hexagon is made by using a scale factor of 6, which applies to the model?

a.) The model represents a reduction

b.) each side of the model is 15 feet long

c.) the model is proportional to the original hexagon

d.) one side of the model can be 8.5 feet long

e.) the scale factor is divided by 2.5 to get the dimensions of the model

maks197457 [2]4 years ago
4 0
<h2> b &c</h2>

Step-by-step explanation:

just took quiz

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1 17/20

the 1 is ur whole number....it stays ur whole number
17/20 = 0.85

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5 0
3 years ago
Samantha drove her car with a full tank of gas 268 miles to her friends town for an average of 22.68 miles/gallons and then refi
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Answer:

23.64 gallons

Step-by-step explanation:

Given:

Samantha drove her car with a full tank of gas 268 miles to her friends town

for an average of 22.68 miles/gallons and then refilled her car with gas.

Question asked:

How much gas was used by the car on the trip ?

Solution:

<u><em>By unitary method:</em></u>

<u>As  average of car is given 22.68 miles/gallons:</u>

For 22.68 miles, number of gallons of gas used = 1

For 1 mile, number of gallons of gas used = \frac{1}{22.68}

For 268 mile, number of gallons of gas used = \frac{1}{22.68}\times268

                                                                           = \frac{268}{22.68} =11.82

Now, to find total gas used in whole trip :-

11.82 + 11.82 = 23.64 gallons of gas

Thus, 23.64 gallons of gas used by the car on the trip.

4 0
4 years ago
Find the volume of the figure shown below.
allsm [11]

Answer:

B. 30 units³

Step-by-step explanation:

the volume= 5×2×3 = 30

7 0
3 years ago
A company produces mopeds and bicycles. It must produce at least 10 mopeds per month. The company has the equipment to produce o
zepelin [54]

Answer:

3. B. P = 134x + 20y

4. J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)

5. C. 60 mopeds 100 bicycles

Step-by-step explanation:

3. The given information are;

The number of mopeds the company must produce per month = 10

The number of mopeds the company can produce month = 60

The number of bicycles the company can produce per month = 120

The total sum of the produced mopeds and bicycles ≤ 160

The profit on a moped = $134

The profit on a bicycle = $20

Given that the number of moped produced = x and the number of bicycles produced = y

Therefore, we have;

Profit, P = $134 × x + $20 × y

Which gives;

B. P = 134x + 20y

4) From Desmos, using the following constraints;

x + y ≤ 160

10 ≤ x ≤ 60

0 ≤ y ≤ 120 we have;

The vertices of the constraint for the feasible region are;

J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)

5) We note that since the profit from each moped is more than the profit from the sale of each bicycle, the maximum possible number of moped should be produced, while the rest should be used to produce bicycles

Therefore, given that from the vertices, the maximum possible number of moped = 60, the number of bicycles to be produced should be 160 - 60 = 100 bicycles

Which gives;

C. 60 mopeds 100 bicycles.

8 0
3 years ago
The legs of a right triangle are in the ratio 3:4. If the hypotenuse is 10, what is the length of the longer leg?
tatyana61 [14]

Answer:

H^2 = P^2+ B^2

10^2 = 3x^2 +4x^2

100 = 9x^2 + 16x^2

100 = 25x^2

100 ÷ 25 = x^2

4 = x^2

x= 2

Length of longer arm is 4x = 4×2=8

Step-by-step explanation:

8 0
3 years ago
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