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bija089 [108]
3 years ago
8

When a system of equations has no solution, the system is called

Mathematics
2 answers:
Serhud [2]3 years ago
6 0
When a system of equations has no solutions it called an inconsistent system of equations.

When you graph the equations, you will find that they will be parallel to one another. In other words, they won't intersect. On the other hand, a system of equations with one solution when graphed will have a point where they intersect. That intersection is the solution to the system of equations.
Dahasolnce [82]3 years ago
3 0
No solution is what it is called
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Find the coordinates of the midpoint (-3,13) (10,-4)
xenn [34]

Answer:

The answer is

<h2>( \frac{7}{2}  \: , \:  \frac{9}{2} )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-3,13) and (10,-4)

The midpoint M is

<h3>M  = ( \frac{ - 3 + 10}{2}  , \:  \frac{13 - 4}{2} ) \\</h3>

We have the final answer as

<h3>( \frac{7}{2}  \: , \:  \frac{9}{2} )</h3>

Hope this helps you

5 0
3 years ago
Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the
m_a_m_a [10]

Answer:

Required volume is \frac{4864\pi}{3} unit.

Step-by-step explanation:

Given equations of curves,

y=32-x^2, y=x^2

substitute second in first we will get,

x^2=36-x^2\implies x^2=16\implies x=\pm 4

When x=4, y=16 and x=-4, y=16. Thus both curves intersect at the points (4,16),(-4,16). And thus -4.

Considering width of the representative rectangle as \Delta x which is parallel to x-axis because of considering cylindrical shell. Therefore volume of the shell is given by,

V_{Shell}=(\textit{Length of box})\times (\textit{Width of box})\times (\textit{Thikness of box})

Now,

Length of generating box=Length of \Delta x from line x=4(axis of revolution)=circumference of the shell=(4-x)

Width of box=(36-x^2)-x^2

Hence,

V_{Shell}

=\int_{-4}^{4}2\pi (4-x)(36-2x^2)dx

=2\pi\int_{-4}^{4}(144-36x-8x^2+2x^3)dx

=2\pi\{144\big[x\big]_{-4}^{4}-18\big[x^2\big]_{-4}^{4}-\frac{8}{3}\big[x^3\big]_{-4}^{4}+\frac{1}{2}\big[x^4\big]_{-4}^{4}\}

=\frac{4864\pi}{3}

which is required volume of generating area.

3 0
3 years ago
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