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Veronika [31]
3 years ago
13

Find the coordinated if point G that lies along the directed line segment from F(-1,-1) to H(-8,20) and partitions the segment i

n the ratio of 5:2

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

The parametric segment between F and H is

P(t) = (1-t)F + tH

P(0)=F, P(1)=H.

We want P such that FP:PH=5:2

That corresponds to t = \dfrac{5}{5+2} = \dfrac 5 7

P(\frac 5 7) = \frac 2 7 F + \frac 5 7 H = \left( \dfrac{ 2(-1)+5(-8)}{7},  \dfrac{ 2(-1)+5(20)}{7} \right) = (-42/7, 98/7) = (-6, 14)

Answer: (-6, 14)

Plot (-1,-1), (-6,14), (-8,20)

Check out the edge lengths

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Answer:

4/15+1/5+5/12=53/60 so

7/60

Hope This Helps!!!

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If dan has $3.75 and he spends 1/3 of it how much does he have left
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11. Let f(x) = 2x² + 7x + 5
Lady_Fox [76]

Answer:

(x+1)(2x+5)

Step-by-step explanation:

f(x) = 2x² + 7x + 5

Factor the expression by grouping. First, the expression needs to be rewritten as 2x²+ax+bx+5. To find a and b, set up a system to be solved.

a+b=7

ab=2×5=10

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 10.

1,10

2,5

Calculate the sum for each pair.

1+10=11

2+5=7

The solution is the pair that gives sum 7.

a=2

b=5

2x²+7x+5 as (2x²+2x)+(5x+5).

(2x²+2x)+(5x+5)

Factor out 2x in the first and 5 in the second group.

2x(x+1)+5(x+1)

Factor out common term x+1 by using distributive property.

(x+1)(2x+5)

7 0
3 years ago
I am trying to graduate HS please help me out!!!
vichka [17]
1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:
<span> 
 A=(b1+b2/2)h
</span><span> 
 A is the area of the trapezoid.
</span><span> b1 is the larger base of the trapezoid (b1=16-4=12 ft).
</span><span> b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
</span><span> h is the height of the trapezoid (h=12-4=8 ft)
</span><span> 
 2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:
</span><span> 
 A=(b1+b2/2)h
</span><span> A=(12 ft+6 ft/2)(8 ft)
</span><span> A=9 ftx8ft
</span><span> A=72 ft² 
</span><span> 
 3. </span><span>The length of fencing is:</span>  a²=b²+c² a=√b²+c² a=√(8 ft)²+(6 ft)² a=10 ft  Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft
6 0
3 years ago
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