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vovangra [49]
3 years ago
9

Ms. Ashley planned to stay at a hotel that charges $88 per night for a room and $20 per night in fees and taxes. She used this e

xpression to calculate the total cost of staying in the hotel for n nights. 88n 20n
Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Step-by-step explanation:

Since 88 is for one night and 20 per night in fees and taxes.

Step 1 : Calculate for $88

\frac{88n}{88}  \\make N the subject of formula

n =  \frac{88}{88}  \\

N= 1

Step 2: Calculate for $20

\frac{20n}{20}  \\

make N the subject of formula

n =  \frac{20}{20}

N = 1

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What is the area of the shaded sector? (Round to the nearest tenth)<br> 10<br> 38
masya89 [10]

Answer:

33.1

Step-by-step explanation:

First you need to find the area of the circle. The radius is 10 which means that the area is 314. Since a circle has 360 degrees, and the shaded area is 38 degrees, you need to divide 314 by 360 which is 0.87. Then multiply by 38 because the shaded sector is 38. 0.87 x 38 = 33.1.

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Part 1. Please show work. Please assist me with these math problems. ​
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Answer: 1) 2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

              2) 2,490,924

              3) Neither

<u>Step-by-step explanation:</u>

S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784

\sum^8_{k=1}S_k\\\\=S_1+S_2+S_3+S_4+S_5+S_6+S_7+S_8\\\\= 2,490,924\\

Neither

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                        S₂ - S₁          S₃ - S₂           S₄ - S₃      

                      3 - 2 = 1       4 - 3 = 1          9 - 4 = 5

Not geometric because the ratios between each of the terms is not the same.                

                       \dfrac{S_2}{S_1}=\dfrac{S_3}{S_2}\qquad \rightarrow \dfrac{3}{2}=\dfrac{4}{3}\qquad \rightarrow \text{cross multiply to get}: 9\neq 8

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