3 years ago

Independent Practice

1 answer:

3 0

About 6 times. 6.4 to be exact!

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Alecsey [184]

I think all of the above apply

5 0

3 years ago

vivado [14]

Answer:

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$

Step-by-step explanation:

we have

$f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}$

$g(x)=\frac{1}{x^{2}+1}$

we know that

In the function

$f(g(x))$

The variable of the function f is now the function g(x)

substitute

$f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}$

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$

4 0

3 years ago

BigorU [14]

Answer:

because it may not be suitable for all the time

4 0

3 years ago

Whitepunk [10]

i think it is D because the patten is non linear

4 0

3 years ago

saul85 [17]

The width of the rug is 8

7 0

3 years ago