Question

john is placing cement tiles for a patio in a rectangle surrounding a rectangular fire pit. The fire pit has a width of x ft and a length that is 5 times the width. The entire patio is 6ft wider and 19 ft longer than the fire pit. What is the area that he will need to buy tiles for?

Answer 1

Answer:

49x + 114

Step-by-step explanation:

[   [ fireplace ] x   = area of 5$x^{2}$                   ]  x + 6

     5x

   patio               = area of 5$x^{2}$ + 49x + 114

5x + 19

 

(5x + 19) ( x + 6) = 5$x^{2}$ + 19x + 30x + 114

(5$x^{2}$ + 49x + 114)                     -   (5$x^{2}$ )                         =           49x + 114

(area of patio and fireplace) - (area of fireplace)     =       (area of patio only)