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Delvig [45]
4 years ago
8

What is the midpoint of a segment whose endpoints are (5, 8) and (11, 6)?

Mathematics
1 answer:
maw [93]4 years ago
7 0
Use the midpoint formula for the midpoint (xm, ym) between (x1,y1) and (x2,y2);
xm = (x1 +x2)/2
ym = (y1 +y2)/2

Because (x1,y1) = (5,8) and (x2,y2) = (11,6), therefore
xm = (x1 + x2)/2 = (5+11)2 =8
ym = (8+6)/2 = 7
The midpoint is (8,7).

Answer: a

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Ostrovityanka [42]
160in 5x8=40x4=160 is the answer to ur question
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Find the value of :<br><img src="https://tex.z-dn.net/?f=%20%5Csf%20log_%7B3%20%5Csqrt%7B2%7D%20%7D%28324%29%20" id="TexFormula1
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Answer:

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Step-by-step explanation:

Is that a log with the base of   3√(2)  ?

If so....my calculator says the answer is   4

Let's see if we can do it w/ou the calculator:

3 sqrt(2)^x = 324 =  3^4 * 2^2     Now 'LOG' both sides:

x log (3 sqrt 2)  =   log (3^4 *2^2)  =  4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)

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8 0
3 years ago
Help me ASAP for this question
ludmilkaskok [199]

Answer:

Your answer is 7

Hope this helps!

Step-by-step explanation:

You plug 14 in for x then just do 14-7 and you will get 7

7 0
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