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Novosadov [1.4K]
3 years ago
5

Can someone help me with this question ASAP!

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0

Answer:

2700

Step-by-step explanation:

i think it is becaus you have to do l x w x h

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Anusha is walking on a hiking trail at a rate of 3/4 miles in 1/4 hour. At this rate, how far will Anusha walk in an hour?
kherson [118]
3 miles. Using cross-multiplication, 3×4 = 12 and 4×1 = 4, so 12/4 = 3.
3 0
3 years ago
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A group of transfer bound students wondered if they will spend the same mean amount on texts and supplies each year at their fou
Jet001 [13]

Answer:

We accept H₀. We don´t have enough evidence to support the difference between the two means

Step-by-step explanation:

Group 1 : Comunity College

Sample:

size  :   n₁  = 54

Sample mean    x₁  = 947

Sample standard deviation     s₁ = 254

Group 2 : Local University

Sample

size  :  n₂  =  66

Sample mean :  x₂  = 1011

Sample standard deviation    s₂  =  87

Significance level  α  = 0,05      α  =  5 %      CI = 95 %

Both samples are with n> 30 so we can use z table for the test

from z-table we find  z(c)  =  1,96

The problem statement establishes to run a hypothesis test to determine if the means are statistically the same  ( or different) then we use two-tail-test

Hypothesis Test

Null Hypothesis                        H₀             x₁   -  x₂  = 0 or    x₁  = x₂

Alternative hypothesis             Hₐ             x₁  -  x₂  ≠  0  or    x₁ ≠ x₂

To calculate

z(s)  =  (  x₁   -  x₂  ) / √ s₁²/n₁  + s₂²/n₂ )

z(s)  =  947  -  1011 / √  (254)²/54   +  (87)² / 66

z(s) = -  64  /√ 1194,74  +  114,68

z(s) =  - 64  / 36,185

z(s) =  - 1,77

Comparing modules of  |z(c)|  and |z(s)|

z(s) < z(c)

Then z(s) is in the acceptance region we accept H₀ . There is not enough evidence to support differences in the means of the two groups

3 0
3 years ago
Please help fast! Rosa's friend Jake claims that he can read minds. To test Jake's abilities, Rosa chooses 3 different numbers
grigory [225]

Jake's guesses are illustrations of probabilities.

The probability that Jake's guesses are correct is 1/720

The sample size is:

\mathbf{n = 10} --- 10 different numbers

The probability that Jake's guesses are correct is as follows:

  • 1st guess = 1/10
  • 2nd guess = 1/9
  • 3rd guess = 1/8

So, the required probability is:

\mathbf{Pr = \frac{1}{10} \times \frac 19 \times \frac 18}

\mathbf{Pr = \frac{1}{720} }

Hence, the probability that Jake's guesses are correct is 1/720

Read more about probabilities at:

brainly.com/question/11234923

5 0
3 years ago
Fill in the blanks.<br> 3 + (2 + 5) + (3 + 2) +_ <br><br> 3 + _ = 9 + 3
solong [7]

Answer:

3 + (2 + 5) =(3 + 2) +<u>5</u>_

3 + <u>9</u>_ = 9 + 3

6 0
3 years ago
PLZ ANSWER 20 POINTS
Nataliya [291]
B. but im not entirely sure
3 0
3 years ago
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